Here’s a “valid” way of initializing such a monstrosity: struct bar; struct foo { int y; int bar::* whatever; }; struct bar { foo aFoo; }; int bar::* foo::* ptr = &foo::whatever; As we can see, ptr is a pointer to a member of foo (foo::*, reading right to left), where that member is itself … Read more
I hope this example will clear things for you //we have a class struct X { void f() {} void g() {} }; typedef void (X::*pointer)(); //ok, let’s take a pointer and assign f to it. pointer somePointer = &X::f; //now I want to call somePointer. But for that, I need an object X x; … Read more
There isn’t anything wrong with using function pointers. However, pointers to non-static member functions are not like normal function pointers: member functions need to be called on an object which is passed as an implicit argument to the function. The signature of your member function above is, thus void (aClass::*)(int, int) rather than the type … Read more