It doesn’t quite work that way in Python. Python passes references to objects. Inside your function you have an object — You’re free to mutate that object (if possible). However, integers are immutable. One workaround is to pass the integer in a container which can be mutated: def change(x): x[0] = 3 x = [1] … Read more
Types of Things in Swift The rule is: Class instances are reference types (i.e. your reference to a class instance is effectively a pointer) Functions are reference types Everything else is a value type; “everything else” simply means instances of structs and instances of enums, because that’s all there is in Swift. Arrays and strings … Read more
The short answer is, Python always does pass-by-value, but every Python variable is actually a pointer to some object, so sometimes it looks like pass-by-reference. In Python every object is either mutable or non-mutable. e.g., lists, dicts, modules and Pandas data frames are mutable, and ints, strings and tuples are non-mutable. Mutable objects can be … Read more
When you compile a number literal in Java and assign it to a Integer (capital I) the compiler emits: Integer b2 =Integer.valueOf(127) This line of code is also generated when you use autoboxing. valueOf is implemented such that certain numbers are “pooled”, and it returns the same instance for values smaller than 128. From the … Read more
You can change what foo points to using y: Foo foo = new Foo(“1”); void Bar(ref Foo y) { y = new Foo(“2”); } Bar(ref foo); // foo.Name == “2”
It used to be generally recommended best practice1 to use pass by const ref for all types, except for builtin types (char, int, double, etc.), for iterators and for function objects (lambdas, classes deriving from std::*_function). This was especially true before the existence of move semantics. The reason is simple: if you passed by value, … Read more
Rules of thumb for C++11: Pass by value, except when you do not need ownership of the object and a simple alias will do, in which case you pass by const reference, you must mutate the object, in which case, use pass by a non-const lvalue reference, you pass objects of derived classes as base … Read more
It’s by value according to the PHP Documentation. By default, function arguments are passed by value (so that if the value of the argument within the function is changed, it does not get changed outside of the function). To allow a function to modify its arguments, they must be passed by reference. To have an … Read more
For the second part of your question, see the array page of the manual, which states (quoting) : Array assignment always involves value copying. Use the reference operator to copy an array by reference. And the given example : <?php $arr1 = array(2, 3); $arr2 = $arr1; $arr2[] = 4; // $arr2 is changed, // … Read more
Objects aren’t passed at all. By default, the argument is evaluated and its value is passed, by value, as the initial value of the parameter of the method you’re calling. Now the important point is that the value is a reference for reference types – a way of getting to an object (or null). Changes … Read more