Try the following expression: ^\d+\.\d{0,2}$ If you want the decimal places to be optional, you can use the following: ^\d+(\.\d{1,2})?$ EDIT: To test a string match in Javascript use the following snippet: var regexp = /^\d+\.\d{0,2}$/; // returns true regexp.test(‘10.5’)
This is just for fun, as you already stated and I created a new answer because this one is in a different vein. But I still feel like there are a few random passerby’s who are ignoring the futility of the problem. So let’s start by addressing your points: Firstly: Genuine compatibility data relating to … Read more
DECIMAL and NUMERIC. The recommended Java mapping for the DECIMAL and NUMERIC types is java.math.BigDecimal. The java.math.BigDecimal type provides math operations to allow BigDecimal types to be added, subtracted, multiplied, and divided with other BigDecimal types, with integer types, and with floating point types. The method recommended for retrieving DECIMAL and NUMERIC values is ResultSet.getBigDecimal. … Read more
Building on Brian’s and Stephen’s answers, here’s some complete code: module NumericLiteralG = let inline FromZero() = LanguagePrimitives.GenericZero let inline FromOne() = LanguagePrimitives.GenericOne let inline FromInt32 (n:int) = let one : ^a = FromOne() let zero : ^a = FromZero() let n_incr = if n > 0 then 1 else -1 let g_incr = if … Read more
If you happen to be using ASP.NET MVC 4 onwards, check this post: Localizing Default Error Messages in ASP.NET MVC and WebForms Basically you have to add the following piece of code in your Application_Start() method in Global.asax: ClientDataTypeModelValidatorProvider.ResourceClassKey = “Messages”; DefaultModelBinder.ResourceClassKey = “Messages”; Right click your ASP.NET MVC project in Solution Explorer inside Visual … Read more
Section 3.10.2 of the JLS talks about floating-point literals in Java. In short, provide the decimal part as if it were scientific notation, but instead of x 10^23 you would write e23: 3.30e23 To write one with a negative exponent, you can do that easily also for 6.67 x 10^(-11): 6.67e−11
As it turns out .toFixed() returns strings – Try adding parseFloat before comparing the values to see the result: console.log(parseFloat(value) < parseFloat(max)); // —- now true
I think that what he wants is to have a string split into substrings of size 4. Then I would do this in a loop: List<String> strings = new ArrayList<String>(); int index = 0; while (index < text.length()) { strings.add(text.substring(index, Math.min(index + 4,text.length()))); index += 4; }
This question is actually a very interesting one which mathematicians have devoted a fair bit of thought to. You can read about it in this article, which is a fascinating and accessible read. Briefly, a guy named Tibor Rado set out to find some really big, but still well-defined, numbers by defining a sequence called … Read more
I’m pretty sure you can do this with: float(“8.99284722486562e-02”) # and now with ’rounding’ “{:.8f}”.format(float(“8.99284722486562e-02”))