sizeof returns an unsigned integer, so TOTAL_ELEMENTS is also unsigned. d is signed. Initially, d is -1. However, when doing the comparison, d is implicitly typecast to unsigned, so it is no longer -1 when being compared to TOTAL_ELEMENTS, it is actually UINT_MAX (which is 4294967295 on my machine, but might differ for others). Also, … Read more
The primary advantage of two’s complement over one’s complement is that two’s complement only has one value for zero. One’s complement has a “positive” zero and a “negative” zero. Next, to add numbers using one’s complement you have to first do binary addition, then add in an end-around carry value. Two’s complement has only one … Read more
This is a very subtle error. What you are seeing is a consequence of there being no negative integer literals in C++. If we look at [lex.icon] we get that a integer-literal, integer-literal decimal-literal integer-suffixopt […] can be a decimal-literal, decimal-literal: nonzero-digit decimal-literal ’ opt digit where digit is [0-9] and nonzero-digit is [1-9] and … Read more
It depends on the machine you’re targeting. On a machine that uses a 2’s complement representation for integers there’s no difference at bit-level between 0 and -0 (they have the same representation) If your machine used one’s complement, you definitely could 0000 0000 -> signed 0 1111 1111 -> signed −0 Obviously we’re talking about … Read more
Instead of writing a function to do this check, you should just be able to use this expression: (number < 0) Javascript will evaluate this expression by first trying to convert the left hand side to a number value before checking if it’s less than zero, which seems to be what you wanted. Specifications and … Read more
Both definitions of modulus of negative numbers are in use – some languages use one definition and some the other. If you want to get a negative number for negative inputs then you can use this: int r = x % n; if (r > 0 && x < 0) { r -= n; } … Read more
Just do something like value = value < 0 ? 0 : value; or if (value < 0) value = 0; or value = Math.max(0, value);
If all your columns are numeric, you can use boolean indexing: In [1]: import pandas as pd In [2]: df = pd.DataFrame({‘a’: [0, -1, 2], ‘b’: [-3, 2, 1]}) In [3]: df Out[3]: a b 0 0 -3 1 -1 2 2 2 1 In [4]: df[df < 0] = 0 In [5]: df Out[5]: … Read more
It behaves as it should a % b = a – a / b * b; i.e. it’s the remainder. You can do (a % b + b) % b This expression works as the result of (a % b) is necessarily lower than b, no matter if a is positive or negative. Adding b … Read more
Just call Math.abs. For example: int x = Math.abs(-5); Which will set x to 5. Note that if you pass Integer.MIN_VALUE, the same value (still negative) will be returned, as the range of int does not allow the positive equivalent to be represented.