You could take a cue from nature and modify your second idea. Once you generate your continents (which are all about the same size), get them to randomly move and rotate and collide and deform each other and drift apart from each other. (Note: this may not be the easiest thing ever to implement.) Edit: … Read more
Use Object#toString(). String string = map.toString(); That’s after all also what System.out.println(object) does under the hoods. The format for maps is described in AbstractMap#toString(). Returns a string representation of this map. The string representation consists of a list of key-value mappings in the order returned by the map’s entrySet view’s iterator, enclosed in braces (“{}”). … Read more
There is such a method in groovy, it is called collect, for example: assert [1, 2, 3].collect { it * 2 } == [2, 4, 6] http://docs.groovy-lang.org/next/html/documentation/working-with-collections.html#_iterating_on_a_list
A std::map is an associative container, that allows you to have a unique key associated with your type value. For example, void someFunction() { typedef std::map<std::string, int> MapType; MapType myMap; // insertion myMap.insert(MapType::value_type(“test”, 42)); myMap.insert(MapType::value_type(“other-test”, 0)); // search auto it = myMap.find(“test”); if (it != myMap.end()) std::cout << “value for ” << it->first << ” … Read more
There is no such class in the Java API. The Apache Commons class you want is going to be one of the implementations of BidiMap. As a mathematician, I would call this kind of structure a bijection.
The existing answers to this question are very out of date. With a recent GCC and GDB it Just WorksTM thanks to the built-in Python support in GDB 7.x and the libstdc++ pretty printers that come with GCC. For the OP’s example I get: (gdb) print m $1 = std::map with 2 elements = {[1] … Read more
You need to stream the entries and collect them in a new map: Map<String, String> result = map.entrySet() .stream() .collect(Collectors.toMap(Entry::getKey, e -> String.valueOf(e.getValue()));
Some Map implementations are allowed to have null values, eg HashMap, in this case if get(key) returns null it does not guarantee that there is no entry in the map associated with this key. So if you want to know if a map contains a key use Map.containsKey. If you simply need a value mapped … Read more
std::map::find returns an iterator to the found element (or to the end() if the element was not found). So long as the map is not const, you can modify the element pointed to by the iterator: std::map<char, int> m; m.insert(std::make_pair(‘c’, 0)); // c is for cookie std::map<char, int>::iterator it = m.find(‘c’); if (it != m.end()) … Read more
As many people pointed out the hashCode() method was to blame. It was only generating around 20,000 codes for 26 million distinct objects. That is an average of 1,300 objects per hash bucket = very very bad. However if I turn the two arrays into a number in base 52 I am guaranteed to get … Read more