Because \ begin escape sequences only when they are valid escape sequences. >>> ‘\n’ ‘\n’ >>> r’\n’ ‘\\n’ >>> print ‘\n’ >>> print r’\n’ \n >>> ‘\s’ ‘\\s’ >>> r’\s’ ‘\\s’ >>> print ‘\s’ \s >>> print r’\s’ \s Unless an ‘r’ or ‘R’ prefix is present, escape sequences in strings are interpreted according to … Read more
You need to escape it with two backslashes \\? See this for more details: http://www.trans4mind.com/personal_development/JavaScript/Regular%20Expressions%20Simple%20Usage.htm
No. Escaping / externalizing the string is your only choice.
Python caches integers in the range [-5, 256], so integers in that range are usually but not always identical. What you see for 257 is the Python compiler optimizing identical literals when compiled in the same code object. When typing in the Python shell each line is a completely different statement, parsed and compiled separately, … Read more
Per https://docs.python.org/3/reference/lexical_analysis.html#integer-literals: Integer literals are described by the following lexical definitions: integer ::= decimalinteger | octinteger | hexinteger | bininteger decimalinteger ::= nonzerodigit digit* | “0”+ nonzerodigit ::= “1”…”9″ digit ::= “0”…”9″ octinteger ::= “0” (“o” | “O”) octdigit+ hexinteger ::= “0” (“x” | “X”) hexdigit+ bininteger ::= “0” (“b” | “B”) bindigit+ octdigit ::= … Read more
((short)2) Yeah, it’s not strictly a short literal, more of a casted-int, but the behaviour is the same and I think there isn’t a direct way of doing it. That’s what I’ve been doing because I couldn’t find anything about it. I would guess that the compiler would be smart enough to compile this as … Read more
In Java, integer literals are of type int by default. For some other types, you may suffix the literal with a case-insensitive letter like L, D, F to specify a long, double, or float, respectively. Note it is common practice to use uppercase letters for better readability. The Java Language Specification does not provide the … Read more
One reason to declare constants in a multiplicative way is to improve readability, while the run-time performance is not affected. Also, to indicate that the writer was thinking in a multiplicative manner about the number. Consider this: double memoryBytes = 1024 * 1024 * 1024; It’s clearly better than: double memoryBytes = 1073741824; as the … Read more
Because 2000 is an int which is usually 32-bit. Just use 2000LL. Using LL suffix instead of ll was suggested by @AdrianMole in, now deleted, comment. Please check his answer. By default, integer literals are of the smallest type that can hold their value but not smaller than int. 2000 can easily be stored in … Read more
The r means that the string is to be treated as a raw string, which means all escape codes will be ignored. For an example: ‘\n’ will be treated as a newline character, while r’\n’ will be treated as the characters \ followed by n. When an ‘r’ or ‘R’ prefix is present, a character … Read more