Combine a list of data frames into one data frame by row
Use bind_rows() from the dplyr package: bind_rows(list_of_dataframes, .id = “column_label”)
Use bind_rows() from the dplyr package: bind_rows(list_of_dataframes, .id = “column_label”)
itertools.product Available from Python 2.6. import itertools somelists = [ [1, 2, 3], [‘a’, ‘b’], [4, 5] ] for element in itertools.product(*somelists): print(element) Which is the same as, for element in itertools.product([1, 2, 3], [‘a’, ‘b’], [4, 5]): print(element)
Yes, pretty much. List<T> is a generic class. It supports storing values of a specific type without casting to or from object (which would have incurred boxing/unboxing overhead when T is a value type in the ArrayList case). ArrayList simply stores object references. As a generic collection, List<T> implements the generic IEnumerable<T> interface and can … Read more
In python 2 only (not python 3): assert not isinstance(lst, basestring) Is actually what you want, otherwise you’ll miss out on a lot of things which act like lists, but aren’t subclasses of list or tuple.
The easiest way to solve the problem is to group the elements based on their value, and then pick a representative of the group if there are more than one element in the group. In LINQ, this translates to: var query = lst.GroupBy(x => x) .Where(g => g.Count() > 1) .Select(y => y.Key) .ToList(); If … Read more
If you mean an in-place sort (i.e. the list is updated): people.Sort((x, y) => string.Compare(x.LastName, y.LastName)); If you mean a new list: var newList = people.OrderBy(x=>x.LastName).ToList(); // ToList optional
You don’t need to define intersection. It’s already a first-class part of set. >>> b1 = [1,2,3,4,5,9,11,15] >>> b2 = [4,5,6,7,8] >>> set(b1).intersection(b2) set([4, 5])
You cannot, because IEnumerable<T> does not necessarily represent a collection to which items can be added. In fact, it does not necessarily represent a collection at all! For example: IEnumerable<string> ReadLines() { string s; do { s = Console.ReadLine(); yield return s; } while (!string.IsNullOrEmpty(s)); } IEnumerable<string> lines = ReadLines(); lines.Add(“foo”) // so what is … Read more
Functional approach: Python 3.x >>> x = [1,2,3,2,2,2,3,4] >>> list(filter((2).__ne__, x)) [1, 3, 3, 4] or >>> x = [1,2,3,2,2,2,3,4] >>> list(filter(lambda a: a != 2, x)) [1, 3, 3, 4] Python 2.x >>> x = [1,2,3,2,2,2,3,4] >>> filter(lambda a: a != 2, x) [1, 3, 3, 4]
use reversed() function: reversed(range(10)) It’s much more meaningful. Update: If you want it to be a list (as btk pointed out): list(reversed(range(10))) Update: If you want to use only range to achieve the same result, you can use all its parameters. range(start, stop, step) For example, to generate a list [5,4,3,2,1,0], you can use the … Read more