I had this error and I used the json.dump the wrong way around: Correct way: with open(“Jello.json”, “w”) as json_file: json.dump(object_to_be_saved, json_file) Wrong way: I did it the other way around json.dump(json_file, object_to_be_saved)… Thanks Python.
You can use Json.NET to deserialize your json string as (with some modifications to your classes) var yourObject = JsonConvert.DeserializeObject<Root>(jsonstring); public class Root { public Profile[] Profile; } public class Profile { public string Name { get; set; } public string Last { get; set; } public Client Client { get; set; } public DateTime … Read more
Basic console.log will not go through long and complex object, and may decide to just print [Object] instead. A good way to prevent that in node.js is to use util.inspect: ‘use strict’; const util = require(‘util’), obj = /*Long and complex object*/; console.log(util.inspect(obj, {depth: null})); //depth: null tell util.inspect to open everything until it get … Read more
There is an easier way to do it, in the Query Editor on the column you want to read as a json: Right click on the column Select Transform>JSON then the column becomes a Record that you can split in every property of the json using the button on the top right corner.
If you don’t want to extend DefaultPrettyPrinter you can also just set the indentArraysWith property externally: ObjectMapper objectMapper = new ObjectMapper(); objectMapper.enable(SerializationFeature.INDENT_OUTPUT); DefaultPrettyPrinter prettyPrinter = new DefaultPrettyPrinter(); prettyPrinter.indentArraysWith(DefaultIndenter.SYSTEM_LINEFEED_INSTANCE); String json = objectMapper.writer(prettyPrinter).writeValueAsString(object);
The first argument passed to pgsql function json_populate_recordsetshould be a row type. If you want to use the json array to populate the existing table anoop you can simply pass the table anoop as the row type like this: insert into anoop select * from json_populate_recordset(null::anoop, ‘[{“id”:67272,”name”:”EE_Quick_Changes_J_UTP.xlsx”}, {“id”:67273,”name”:”16167.txt”}, {“id”:67274,”name”:”EE_12_09_2013_Bcum_Searchall.png”}]’); Here the null is the default … Read more
No additional library is needed: val jsonObj = JSONObject(jsonString) val map = jsonObj.toMap() where toMap is: fun JSONObject.toMap(): Map<String, *> = keys().asSequence().associateWith { when (val value = this[it]) { is JSONArray -> { val map = (0 until value.length()).associate { Pair(it.toString(), value[it]) } JSONObject(map).toMap().values.toList() } is JSONObject -> value.toMap() JSONObject.NULL -> null else -> value … Read more
context.Response.Write( jsonSerializer.Serialize( new { query = “Li”, suggestions = new[] { “Liberia”, “Libyan Arab Jamahiriya”, “Liechtenstein”, “Lithuania” }, data = new[] { “LR”, “LY”, “LI”, “LT” } } ) );
A slightly prettier version of what you have: if let json = try? JSONSerialization.jsonObject(with: data, options: .mutableContainers), let jsonData = try? JSONSerialization.data(withJSONObject: json, options: .prettyPrinted) { print(String(decoding: jsonData, as: UTF8.self)) } else { print(“json data malformed”) }
12cR2 (available in the Oracle Cloud) supports this natively. SQL> select JSON_ARRAY(EMPLOYEE_ID, FIRST_NAME,LAST_NAME) from HR.EMPLOYEES; JSON_ARRAY(EMPLOYEE_ID,FIRST_NAME,LAST_NAME) ——————————————————————————– [100,”Steven”,”King”] [101,”Neena”,”Kochhar”] or SQL> select JSON_OBJECT(‘ID’ is EMPLOYEE_ID , ‘FirstName’ is FIRST_NAME,’LastName’ is LAST_NAME) from HR.EMPLOYEES; JSON_OBJECT(‘ID’ISEMPLOYEE_ID,’FIRSTNAME’ISFIRST_NAME,’LASTNAME’ISLAST_NAME) —————————————————————————- {“ID”:100,”FirstName”:”Steven”,”LastName”:”King”} {“ID”:101,”FirstName”:”Neena”,”LastName”:”Kochhar”}