The underlying data source for some implementations of InputStream can signal that the end of the stream has been reached, and no more data will be sent. Until this signal is received, read operations on such a stream can block. For example, an InputStream from a Socket socket will block, rather than returning EOF, until … Read more
You want to call the method without any OpenOption arguments. Files.write(path, content.getBytes()); From the Javadoc: The options parameter specifies how the the file is created or opened. If no options are present then this method works as if the CREATE, TRUNCATE_EXISTING, and WRITE options are present. In other words, it opens the file for writing, … Read more
BufferedWriter is more efficient if you have multiple writes between flush/close the writes are small compared with the buffer size. In your example, you have only one write, so the BufferedWriter just add overhead you don’t need. so does that mean the first example writes the characters one by one and the second first buffers … Read more
I’ve searched all over the web and after reading lot of docs regarding connection timeout exception, the thing I understood is that, preventing SocketTimeoutException is beyond our limit. One way to effectively handle it is to define a connection timeout and later handle it by using a try-catch block. Hope this will help anyone in … Read more
When closing chained streams, you only need to close the outermost stream. Any errors will be propagated up the chain and be caught. Refer to Java I/O Streams for details. To address the issue However, if flush() throws a runtime exception for some reason, then out.close() will never be called. This isn’t right. After you … Read more
I assume you want to be able to use step-through debugging from Eclipse. You can just run the classes externally by setting the built classes in the bin directories on the JRE classpath. java -cp workspace\p1\bin;workspace\p2\bin foo.Main You can debug using the remote debugger and taking advantage of the class files built in your project. … Read more
The listFiles method, with or without a filter does not guarantee any order. It does, however, return an array, which you can sort with Arrays.sort(). File[] files = XMLDirectory.listFiles(filter_xml_files); Arrays.sort(files); for(File _xml_file : files) { … } This works because File is a comparable class, which by default sorts pathnames lexicographically. If you want to … Read more
Place your text file in the /assets directory under the Android project. Use AssetManager class to access it. AssetManager am = context.getAssets(); InputStream is = am.open(“test.txt”); Or you can also put the file in the /res/raw directory, where the file will be indexed and is accessible by an id in the R file: InputStream is … Read more
How can I create new File (from java.io) in memory , not in the hard disk? Maybe you are confusing File and Stream: A File is an abstract representation of file and directory pathnames. Using a File object, you can access the file metadata in a file system, and perform some operations on files on … Read more
Use File‘s getParentFile() method and String.lastIndexOf() to retrieve just the immediate parent directory. Mark’s comment is a better solution thanlastIndexOf(): file.getParentFile().getName(); These solutions only works if the file has a parent file (e.g., created via one of the file constructors taking a parent File). When getParentFile() is null you’ll need to resort to using lastIndexOf, … Read more