Let’s consider how to apply two aggregate functions to the same iterator, which we can only exhaust once. The initial attempt (which hardcodes sum and max for brevity, but is trivially generalizable to an arbitrary number of aggregate functions) might look like this: def max_and_sum_buffer(it): content = list(it) p = sum(content) m = max(content) return … Read more
You need to be careful because erase() will invalidate existing iterators. However, it will return a new valid iterator you can use: for ( it = Entities.begin(); it != Entities.end(); ) { if( (*it)->getXPos() > 1.5f ) { delete * it; it = Entities.erase(it); } else { ++it; } }
You can use boost::multi_index to create a bidirectional map – you can use either value of the pair as a key to do a quick lookup.
The concept of iteration is well documented in the Python documentation. In short, “iterable” is the object which provides the items I want to iterate over. Either it already cintains these items, then it is also called the container. This can be a list, a string, a tuple or anything else which consists of zero … Read more
The particular code sample you are looking at involves a series of transformations. Please note that this is an approximate description of the algorithm. The actual names used by the compiler and the exact code it generates may be different. The idea is the same, however. The first transformation is the “foreach” transformation, which transforms … Read more
There are a few alternatives. The below assumes you are iterating over a 1d NumPy array. Iterate with range for j in range(theta.shape[0]): # or range(len(theta)) some_function(j, theta[j], theta) Note this is the only of the 3 solutions which will work with numba. This is noteworthy since iterating over a NumPy array explicitly is usually … Read more
The cause of this problem is that input is just a string, but what is needed is a list (or an iterable) containing a single element. The error can be removed by adding the following line: input=[input] before X_new_counts = count_vect.transform(input.plot_movie)
If iter.hasNext() is false after iter.next() then it is the last item. Happy coding.
Why reinvent the wheel when you can use os.walk import os for root, dirs, files in os.walk(path): for name in files: print os.path.join(root, name) os.walk is a generator that yields the file names in a directory tree by walking the tree either top-down or bottom-up
You can get an empty list of type Foo through the following syntax: return Collections.<Foo>emptyList().iterator();