Best for Now (43 chars) ^((25[0-5]|(2[0-4]|1\d|[1-9]|)\d)\.?\b){4}$ This version shortens things by another 6 characters while not making use of the negative lookahead, which is not supported in some regex flavors. Newest, Shortest, Least Readable Version (49 chars) ^((25[0-5]|(2[0-4]|1\d|[1-9]|)\d)(\.(?!$)|$)){4}$ The [0-9] blocks can be substituted by \d in 2 places – makes it a bit less … Read more
You can write a script that only return the IP like: /sbin/ifconfig eth0 | grep ‘inet addr’ | cut -d: -f2 | awk ‘{print $1}’ For MAC: ifconfig | grep “inet ” | grep -v 127.0.0.1 | cut -d\ -f2 Or for linux system hostname -i | awk ‘{print $3}’ # Ubuntu hostname -i # … Read more
Don’t parse it. Just ask. import socket try: socket.inet_aton(addr) # legal except socket.error: # Not legal
I would just use the request.remote_ip that’s simple and it works. Any reason you need another method? See: Get real IP address in local Rails development environment for some other things you can do with client server ip’s.
Check if there is an environment variable called: $SSH_CLIENT OR $SSH_CONNECTION (or any other environment variables) which gets set when the user logs in. Then process it using the user login script. Extract the IP: $ echo $SSH_CLIENT | awk ‘{ print $1}’ 1.2.3.4 $ echo $SSH_CONNECTION | awk ‘{print $1}’ 1.2.3.4
The simplest way to get the visitor’s/client’s IP address is using the $_SERVER[‘REMOTE_ADDR’] or $_SERVER[‘REMOTE_HOST’] variables. However, sometimes this does not return the correct IP address of the visitor, so we can use some other server variables to get the IP address. The below both functions are equivalent with the difference only in how and … Read more
See the documentation on how to access the Request object and then get from this same Request object, the attribute remote_addr. Code example from flask import request from flask import jsonify @app.route(“/get_my_ip”, methods=[“GET”]) def get_my_ip(): return jsonify({‘ip’: request.remote_addr}), 200 For more information see the Werkzeug documentation.
Here is a shorter, cleaner way to get the IP address: function get_ip_address(){ foreach (array(‘HTTP_CLIENT_IP’, ‘HTTP_X_FORWARDED_FOR’, ‘HTTP_X_FORWARDED’, ‘HTTP_X_CLUSTER_CLIENT_IP’, ‘HTTP_FORWARDED_FOR’, ‘HTTP_FORWARDED’, ‘REMOTE_ADDR’) as $key){ if (array_key_exists($key, $_SERVER) === true){ foreach (explode(‘,’, $_SERVER[$key]) as $ip){ $ip = trim($ip); // just to be safe if (filter_var($ip, FILTER_VALIDATE_IP, FILTER_FLAG_NO_PRIV_RANGE | FILTER_FLAG_NO_RES_RANGE) !== false){ return $ip; } } } } … Read more
Nope, that is pretty much the best way to do it. As a machine could have several IP addresses you need to iterate the collection of them to find the proper one. Edit: The only thing I would change would be to change this: if (ip.AddressFamily.ToString() == “InterNetwork”) to this: if (ip.AddressFamily == AddressFamily.InterNetwork) There … Read more
If you are running behind a proxy like NGiNX or what have you, only then you should check for ‘x-forwarded-for’: var ip = req.headers[‘x-forwarded-for’] || req.socket.remoteAddress If the proxy isn’t ‘yours’, I wouldn’t trust the ‘x-forwarded-for’ header, because it can be spoofed.