PHP: How can I determine if a variable has a value that is between two distinct constant values?
if (($value > 1 && $value < 10) || ($value > 20 && $value < 40))
if (($value > 1 && $value < 10) || ($value > 20 && $value < 40))
Edit Apr 19, 2013: Modulo function updated to handle boundary cases as noted by aka.nice and arr_sea: static const double _PI= 3.1415926535897932384626433832795028841971693993751058209749445923078164062862089986280348; static const double _TWO_PI= 6.2831853071795864769252867665590057683943387987502116419498891846156328125724179972560696; // Floating-point modulo // The result (the remainder) has same sign as the divisor. // Similar to matlab’s mod(); Not similar to fmod() – Mod(-3,4)= 1 fmod(-3,4)= -3 … Read more
You could use standard stuff from java.util.concurrent: import java.util.concurrent._ val ex = new ScheduledThreadPoolExecutor(1) val task = new Runnable { def run() = println(“Beep!”) } val f = ex.scheduleAtFixedRate(task, 1, 1, TimeUnit.SECONDS) f.cancel(false) Or java.util.Timer: val t = new java.util.Timer() val task = new java.util.TimerTask { def run() = println(“Beep!”) } t.schedule(task, 1000L, 1000L) task.cancel()
You need DATE_ADD/DATE_SUB: AND v.date > (DATE_SUB(CURDATE(), INTERVAL 2 MONTH)) AND v.date < (DATE_SUB(CURDATE(), INTERVAL 1 MONTH)) should work.
You have at least four options: 1. List each case As shown by LightStyle, you can list each case explicitly: switch(myInterval){ case 0: case 1: case 2: doStuffWithFirstRange(); break; case 3: case 4: case 5: doStuffWithSecondRange(); break; case 6: case 7: doStuffWithThirdRange(); break; default: doStuffWithAllOthers(); } 2. Use if / else if / else If … Read more
Use the following the custom class called CustomTimePickerDialog, which I think solve your problem. import java.lang.reflect.Field; import java.util.ArrayList; import java.util.List; import android.app.TimePickerDialog; import android.content.Context; import android.content.DialogInterface; import android.widget.NumberPicker; import android.widget.TimePicker; public class CustomTimePickerDialog extends TimePickerDialog { private final static int TIME_PICKER_INTERVAL = 5; private TimePicker mTimePicker; private final OnTimeSetListener mTimeSetListener; public CustomTimePickerDialog(Context context, OnTimeSetListener listener, … Read more
One simple solution is create interval index from start and end setting closed = both then use get_loc to get the event i.e (Hope all the date times are in timestamps dtype ) df_2.index = pd.IntervalIndex.from_arrays(df_2[‘start’],df_2[‘end’],closed=’both’) df_1[‘event’] = df_1[‘timestamp’].apply(lambda x : df_2.iloc[df_2.index.get_loc(x)][‘event’]) Output : timestamp A B event 0 2016-05-14 10:54:33 0.020228 0.026572 E1 1 … Read more
Use this line: startDate TIMESTAMP := endDate – ($3 || ‘ MONTH’)::INTERVAL; and note the space before MONTH. Basically: You construct a string with like 4 MONTH and cast it with ::type into a proper interval. Edit: I’ have found another solution: You can calculate with interval like this: startDate TIMESTAMP := endDate – $3 … Read more
var helloWorldTimer = NSTimer.scheduledTimerWithTimeInterval(60.0, target: self, selector: Selector(“sayHello”), userInfo: nil, repeats: true) func sayHello() { NSLog(“hello World”) } Remember to import Foundation. Swift 4: var helloWorldTimer = Timer.scheduledTimer(timeInterval: 60.0, target: self, selector: #selector(ViewController.sayHello), userInfo: nil, repeats: true) @objc func sayHello() { NSLog(“hello World”) }