int is a primitive type. Variables of type int store the actual binary value for the integer you want to represent. int.parseInt(“1”) doesn’t make sense because int is not a class and therefore doesn’t have any methods. Integer is a class, no different from any other in the Java language. Variables of type Integer store … Read more
The most naive way would be to iterate over the String and make sure all the elements are valid digits for the given radix. This is about as efficient as it could possibly get, since you must look at each element at least once. I suppose we could micro-optimize it based on the radix, but … Read more
You want to cast the numbers: double num3 = (double)num1/(double)num2; Note: If any of the arguments in C# is a double, a double divide is used which results in a double. So, the following would work too: double num3 = (double)num1/num2; For more information see: Dot Net Perls
You could use this to sort all kind of Objects sort(T[] a, Comparator<? super T> c) Arrays.sort(a, Collections.reverseOrder()); Arrays.sort() cannot be used directly to sort primitive arrays in descending order. If you try to call the Arrays.sort() method by passing reverse Comparator defined by Collections.reverseOrder() , it will throw the error no suitable method found … Read more
Assuming you want a field length of 2 with leading zeros you’d do this: import Foundation for myInt in 1 … 3 { print(String(format: “%02d”, myInt)) } output: 01 02 03 This requires import Foundation so technically it is not a part of the Swift language but a capability provided by the Foundation framework. Note … Read more
Using Math.round() will round the float to the nearest integer.
int myInt = myBoolean ? 1 : 0; ^^ PS : true = 1 and false = 0
Integer.toString calls the static method in the class Integer. It does not need an instance of Integer. If you call new Integer(i) you create an instance of type Integer, which is a full Java object encapsulating the value of your int. Then you call the toString method on it to ask it to return a … Read more
There are multiple ways: String.valueOf(number) (my preference) “” + number (I don’t know how the compiler handles it, perhaps it is as efficient as the above) Integer.toString(number)
string myString = myInt.ToString();