Basically indexOf() is a method belongs to string(array object also), But while calling the function you are passing a number, try to cast it to a string and pass it. document.getElementById(“oset”).innerHTML = timeD2C(timeofday + “”); var timeofday = new Date().getHours() + (new Date().getMinutes()) / 60; function timeD2C(time) { // Converts 11.5 (decimal) to 11:30 (colon) … Read more
Instances of the String constructor have a .search() method which accepts a RegExp and returns the index of the first match. To start the search from a particular position (faking the second parameter of .indexOf()) you can slice off the first i characters: str.slice(i).search(/re/) But this will get the index in the shorter string (after … Read more
Here’s the Underscore way to do it – this augments the core Underscore function with one that accepts an iterator function: // save a reference to the core implementation var indexOfValue = _.indexOf; // using .mixin allows both wrapped and unwrapped calls: // _(array).indexOf(…) and _.indexOf(array, …) _.mixin({ // return the index of the first … Read more
Arrays.asList(A) returns a List<int[]>. This is because it expects an array of objects, not primitive types. Your options include: use Integer[] instead of int[] inline the array, and let autoboxing take care of it; Arrays.asList(3,8,2,5,1,4,7,9) will work fine use Guava’s Ints.asList(int…) method to view the primitive array as a List<Integer>. (Disclosure: I contribute to Guava.) … Read more
If you’re afraid of O(m*n) behaviour – basically, you needn’t, such cases don’t occur naturally – here’s a KMP implementation I had lying around which I’ve modified to take the length of the haystack. Also a wrapper. If you want to do repeated searches, write your own and reuse the borders array. No guarantees for … Read more
You cannot use indexOf to do complicated arrays (unless you serialize it making everything each coordinate into strings), you will need to use a for loop (or while) to search for that coordinate in that array assuming you know the format of the array (in this case it is 2d). var arr = [[2,3],[5,8],[1,1],[0,9],[5,7]]; var … Read more
string[] myarr = new string[] {“s”, “f”, “s”}; int[] v = myarr.Select((b,i) => b == “s” ? i : -1).Where(i => i != -1).ToArray(); This will return 0, 2 If the value does not exist in the array then it will return a int[0]. make an extension method of it public static class EM { … Read more
Well you can use Array.IndexOf: int index = Array.IndexOf(HeaderNamesWbs, someValue); Or just declare HeaderNamesWbs as an IList<string> instead – which can still be an array if you want: public static IList<string> HeaderNamesWbs = new[] { … }; Note that I’d discourage you from exposing an array as public static, even public static readonly. You should … Read more
You don’t need to use LINQ, you can use FindIndex of List<T>: int index = customers.FindIndex(c => c.ID == 150);