In Scala, why is NaN not being picked up by pattern matching?

It is a general rule how 64-bit floating point numbers are compared according to IEEE 754 (not Scala or even Java related, see NaN): double n1 = Double.NaN; double n2 = Double.NaN; System.out.println(n1 == n2); //false The idea is that NaN is a marker value for unknown or indeterminate. Comparing two unknown values should always … Read more

Is there any accuracy gain when casting to double and back when doing float division?

I am going to assume IEEE 754 binary floating point arithmetic, with float 32 bit and double 64 bit. In general, there is no advantage to doing the calculation in double, and in some cases it may make things worse through doing two rounding steps. Conversion from float to double is exact. For the infinite, … Read more

How to check if C++ compiler uses IEEE 754 floating point standard

Actually you have an easier way to achieve this in C++. From the C++ standard 18.2.1.1 the class numeric_limits exists within std. In order to access said static member you simply do this: std::numeric_limits<double>::is_iec559; Or: std::numeric_limits<float>::is_iec559; Which should return true if IEEE 754 is in use, false otherwise. As an alternative method, the second part … Read more

Why is the square root of -Infinity +Infinity in Java? [duplicate]

A NaN is returned (under IEEE 754) in order to continue a computation when a truly undefined (intermediate) result has been obtained. An infinity is returned in order to continue a computation after an overflow has occurred. Thus the behaviour Math.sqrt(Double.NEGATIVE_INFINITY); // NaN is specified because it is known (easily and quickly) that an undefined … Read more

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