Check the post hibernate hql ERROR: Not supported for DML operations in the hibernate users forum. Most likely you called querySt.list(); for your UPDATE query. Instead you should call querySt.executeUpdate();
Joins can only be used when there is an association between entities. Your Employee entity should not have a field named id_team, of type int, mapped to a column. It should have a ManyToOne association with the Team entity, mapped as a JoinColumn: @ManyToOne @JoinColumn(name=”ID_TEAM”) private Team team; Then, the following query will work flawlessly: … Read more
you are using query.setParameter(“searchKeyword”, searchKeyword+”%”); instead of query.setParameter(“searchKeyword”, “%”+searchKeyword+”%”); first one will return rows for Narasimham N Na Nar Nara etc.
I didn’t find any specification of the behavior in the Hibernate docs, but the between operator in HQL is translated to the between operator in SQL, which is inclusive. So between in HQL is also inclusive, that is A between 5 and 10 is equivalent to A >= 5 and A <= 10
Suppose your login table is mapped by a LoginClass class, with emailid and password instance variables. Then you’ll execute something like: Query query = session.createQuery( “select count(*) from LoginClass login where login.emailid=:email and login.password=:password”); query.setString(“email”, “something”); query.setString(“password”, “password”); Long count = (Long)query.uniqueResult(); It should return in count the result you’re looking for. You just have … Read more
Baron Schwartz at MySQLPerformanceBlog.com authored a post about this. I wish there was a magic bullet for this problem, but there isn’t. Summary of the options he presented: On the first query, fetch and cache all the results. Don’t show all results. Don’t show the total count or the intermediate links to other pages. Show … Read more
You have to use the cross join notation: from A as table_a , B as table_b where table_a.c = table_b.c Of course there is no way to implement outer joins in this manner, so you might have some trouble if that’s your case. For the analogous case with criteria refer to: hibernate-criteria-joining-table-without-a-mapped-association
Use the select new map syntax in HQL to fetch the results of each row in a Map. Take a look at the following question, that addresses the issue: How to fetch hibernate query result as associative array of list or hashmap. For instance, the following HQL: select new map(perm.id as pid, perm.name as pname) … Read more
You have no whitespace between lines “and req_t.receiver.id=?2 and req_t.requestType in ?3” + “and NOT EXISTS also check that the ?3 param is not empty list
You can provide limitations by limitstatement in your SQL. And have nativeQuery = true in @Query annotation to set JPA provider(like Hibernate) to consider this as a native SQL query. @Query(nativeQuery = true, value = “SELECT * FROM SLSNotification s WHERE s.userId = :userId ORDER BY snumber DESC LIMIT 20”) List<SLSNotification> getUserIdforManage(@Param(“userId”) String userId); Or … Read more