You need to go via the codecs module and the hex_codec codec (or its hex alias if available*): codecs.encode(b’\x12′, ‘hex_codec’) * From the documentation: “Changed in version 3.4: Restoration of the aliases for the binary transforms”.
Why do you not use the java functionality for that: If your numbers are small (smaller than yours) you could use: Integer.parseInt(hex, 16) to convert a Hex – String into an integer. String hex = “ff” int value = Integer.parseInt(hex, 16); For big numbers like yours, use public BigInteger(String val, int radix) BigInteger value = … Read more
Simply use the hex.DecodeString() function: s := “46447381” data, err := hex.DecodeString(s) if err != nil { panic(err) } fmt.Printf(“% x”, data) Output: 46 44 73 81 Try it on the Go Playground. Note: If you just simply print the byte slice using fmt.Println(data), the printed values will be in decimal format that’s why it … Read more
try this out: var rgbString = “rgb(0, 70, 255)”; // get this in whatever way. var parts = rgbString.match(/^rgb\((\d+),\s*(\d+),\s*(\d+)\)$/); // parts now should be [“rgb(0, 70, 255”, “0”, “70”, “255”] delete (parts[0]); for (var i = 1; i <= 3; ++i) { parts[i] = parseInt(parts[i]).toString(16); if (parts[i].length == 1) parts[i] = ‘0’ + parts[i]; } … Read more
Supposing data is a char*. Working example using std::hex: for(int i=0; i<data_length; ++i) std::cout << std::hex << (int)data[i]; Or if you want to keep it all in a string: std::stringstream ss; for(int i=0; i<data_length; ++i) ss << std::hex << (int)data[i]; std::string mystr = ss.str();
Since alpha value both attenuates the background color and the color value, something like this could do the trick: function rgba2rgb(RGB_background, RGBA_color) { var alpha = RGBA_color.a; return new Color( (1 – alpha) * RGB_background.r + alpha * RGBA_color.r, (1 – alpha) * RGB_background.g + alpha * RGBA_color.g, (1 – alpha) * RGB_background.b + alpha … Read more
C# uses 0x and VB.NET uses &H as the prefix to specify hexadecimal numbers. try this. Public Const temp As Integer = &HE6359A60 Sub Main End Sub And it could be as Uint also: Public Const temp As UInt32 = &HE6359A60UI Sub Main End Sub Check MSDN’s Type Characters (Visual Basic) documentation for defining hexadecimal … Read more
static Random random = new Random(); public static string GetRandomHexNumber(int digits) { byte[] buffer = new byte[digits / 2]; random.NextBytes(buffer); string result = String.Concat(buffer.Select(x => x.ToString(“X2”)).ToArray()); if (digits % 2 == 0) return result; return result + random.Next(16).ToString(“X”); }
As I am on Kotlin 1.3 you may also be interested in the UByte soon (note that it’s an experimental feature. See also Kotlin 1.3M1 and 1.3M2 announcement) E.g.: @ExperimentalUnsignedTypes // just to make it clear that the experimental unsigned types are used fun ByteArray.toHexString() = asUByteArray().joinToString(“”) { it.toString(16).padStart(2, ‘0’) } The formatting option is … Read more