Do not use parenthesis and commas. This is PowerShell (say, arguments are similar to arguments of commands in CMD). That is, call your function like this: ExtendHash $hash1 $hash2 In your case expression ($hash1,$hash2) is an array of two items and you pass this array, one argument, to the function. Such a call fails correctly. … Read more
Using a power of two effectively masks out top bits of the hash code. Thus a poor-quality hash function might perform particularly badly in this scenario. Java’s HashMap mitigates this by mistrusting the object’s hashCode() implementation and applying a second level of hashing to its result: Applies a supplemental hash function to a given hashCode, … Read more
You have some options here. Enumerating through keys: foreach ($key in $var.Keys) { $value = $var[$key] # or $value = $var.$key } Enumerating key-value pairs (which you’ve discovered, but may not be using effectively): foreach ($kvp in $var.GetEnumerator()) { $key = $kvp.Key $val = $kvp.Value }
I ran into the same problem when I tried to implement weak containers. As @plivesey points out in a comment above, this seems to be a bug in Swift 2.2 / Xcode 7.3, but it is expected to work. However, the problem does not occur for some Foundation protocols. For example, this compiles: let container … Read more
Long after the question has been asked, so I don’t expect to earn much rep. However I decided it would be fun to write my own very basic example (in less than 90 lines of code): public struct KeyValue<K, V> { public K Key { get; set; } public V Value { get; set; } … Read more
Set is not a class, it is an interface. So basically you can instantiate only class implementing Set (HashSet, LinkedHashSet orTreeSet) For instance : Set<String> mySet = new HashSet<String>();
At first glance, it appears that x should always equal y, because two sets constructed from the same elements are always equal: >>> x = set([1, “a”, “b”, “c”, “z”, “f”]) >>> y = set([“a”, “b”, “c”, “z”, “f”, 1]) >>> x {1, ‘z’, ‘a’, ‘b’, ‘c’, ‘f’} >>> y {1, ‘z’, ‘a’, ‘b’, ‘c’, … Read more
public static Dictionary<K,V> HashtableToDictionary<K,V> (Hashtable table) { return table .Cast<DictionaryEntry> () .ToDictionary (kvp => (K)kvp.Key, kvp => (V)kvp.Value); }
There is no built-in solution in PowerShell V1 / V2. You will want to use the .NET System.Collections.Specialized.OrderedDictionary: $order = New-Object System.Collections.Specialized.OrderedDictionary $order.Add(“Switzerland”, “Bern”) $order.Add(“Spain”, “Madrid”) $order.Add(“Italy”, “Rome”) $order.Add(“Germany”, “Berlin”) PS> $order Name Value —- —– Switzerland Bern Spain Madrid Italy Rome Germany Berlin In PowerShell V3 you can cast to [ordered]: PS> [ordered]@{“Switzerland”=”Bern”; “Spain”=”Madrid”; … Read more
You need to use an explicit java.util.Iterator to iterate over the Map‘s entry set rather than being able to use the enhanced For-loop syntax available in Java 6. The following example iterates over a Map of Integer, String pairs, removing any entry whose Integer key is null or equals 0. Map<Integer, String> map = … … Read more