There is a way to generate vector images with matplotlob, outputting with the library io to a vector image (SVG) with this approach. I personally tried to run the code of the approach (generate a vectorial histogram) in that webpage as a python file, and it worked. The code: import numpy as np import matplotlib.pyplot … Read more
Very interesting question. I wanted to implement this into mine 4D rendering engine as I was curious how would it look like but I was too lazy and incompetent to handle ND transcendent problems from the math side. Instead I come up with different solution to this problem. Its not a Fibonaci Latice !!! Instead … Read more
If you don’t need the actual euclidean angle, but something that you can use as a base for angle comparisons, then changing to taxicab geometry may be a choice, because you can drop trigonometry and it’s slowness while MAINTAINING THE ACCURACY (or at least with really minor loosing of accuracy, see below). In main modern … Read more
I am sorry to disagree with the answer of Peter Walser. Solving the equations gives on my desk: u = ((bs.y – as.y) * bd.x – (bs.x – as.x) * bd.y) / (bd.x * ad.y – bd.y * ad.x) v = ((bs.y – as.y) * ad.x – (bs.x – as.x) * ad.y) / (bd.x * … Read more
Start with the rightmost point (the point with the biggest x coordinate) Get all edges from this point Follow the edge with the smallest angle to the positive x-axis, and also add it to the solution set From the point reached, follow and add the edge with the smallest angle to the edge you came … Read more
Here’s my own solution, based on the idea in ask Dr. Math. I’d be happy to see your feedback. Disclaimer first. This solution is correct for spheres. Earth isn’t a sphere, and the coordinates system (WGS 84) doesn’t assume it’s a sphere. So this is just an approximation, and I can’t really estimate is error. … Read more
Here’s the mathematical solution which can be applied in any language: x = x0 + r * cos(theta) y = y0 + r * sin(theta) x0 and y0 are the coordinates of the centre, r is the radius, and theta is in radians. The angle is measured anticlockwise from the x-axis. This is the code … Read more
For Firefox you can add -moz-transform: scale(.9999); to make smooth edges. In your case: .triangle { width: 0; height: 0; border-top: 0; border-bottom: 30px solid #666699; border-left: 20px solid transparent; border-right: 20px solid transparent; -moz-transform: scale(.9999); } Will do the trick.
Pick a safe starting point. Can be e.g. the endpoint with maximum x. March along the line segment. Upon encountering any intersection, always turn left and march along this new segment. Upon encountering an endpoint, record it. Goto 2. Stop when you have returned to your starting point. Your list of recorded endpoints now makes … Read more
The Voronoi diagram is just the dual graph of the Delaunay triangulation. So, the edges of the Voronoi diagram are along the perpendicular bisectors of the edges of the Delaunay triangulation, so compute those lines. Then, compute the vertices of the Voronoi diagram by finding the intersections of adjacent edges. Finally, the edges are then … Read more