contacts.ForEach(c => { c.ID = 0; c.GroupID = 0; c.CompanyID = 0; }); It doesn’t have anything to do with LINQ per se; it’s just a simple anonymous method written in lambda syntax passed to the List<T>.ForEach function (which existed since 2.0, before LINQ).
Set a breakpoint inside the loop, then right click on the breakpoint to set the conditions. You can also right click to see the hit count while debugging and reset it if you want. You can set a boolean expression that is evaluated when the breakpoint hits to conditionally break (or just pass over).
Write the clearest code you can, and then benchmark and profile to discover any performance problems. If you do have performance problems, you can experiment with different code to work out whether it’s faster or not (measuring all the time with as realistic data as possible) and then make a judgement call as to whether … Read more
It much depends on the IDE you are using. In Netbeans and IntelliJ you are able to use @var in a comment: /* @var $variable ClassName */ $variable-> The IDE will now know that $variable is of the class ClassName and hint after the ->. You can try it out in your own IDE as … Read more
If you know the number of levels in nested arrays you can simply do nested loops. Like so: // Scan through outer loop foreach ($tmpArray as $innerArray) { // Check type if (is_array($innerArray)){ // Scan through inner loop foreach ($innerArray as $value) { echo $value; } }else{ // one, two, three echo $innerArray; } } … Read more
You should better use iterators for that: // Remove all odd numbers from a QList<int> QMutableListIterator<int> i(list); while (i.hasNext()) { if (i.next() % 2 != 0) i.remove(); }
My question is how does a for each loop work for an empty list ForEach also works in the same way. If the length is zero then loop is never executed. The only difference between them is use ForEach loop when you want to iterate all the items of the list or array whereas in … Read more
Use the second parameter forEach accepts instead, which will be the current index you’re iterating over: n = [1,2,3,5,7,8,9,11,12,13,14,16,17,18,20,21,22]; n.forEach((element, index) => { console.log(element, index); }); If you have two separate arrays to begin with, in each iteration, access the [index] property of the other array: var n = [1, 2, 3, 5, 7, 8, … Read more
The problem is with the first member of the pair, which should be const. Try this: typedef std::map<int, int> map_t; map_t mmap; BOOST_FOREACH( map_t::value_type &i, mmap ) i.second++;
There is an advantage to using std::for_each instead of an old school for loop (or even the newfangled C++0x range-for loop): you can look at the first word of the statement and you know exactly what the statement does. When you see the for_each, you know that the operation in the lambda is performed exactly … Read more