Parameter evaluation order before a function calling in C
No, function parameters are not evaluated in a defined order in C. See Martin York’s answers to What are all the common undefined behaviour that c++ programmer should know about?.
No, function parameters are not evaluated in a defined order in C. See Martin York’s answers to What are all the common undefined behaviour that c++ programmer should know about?.
new-if is a function. When a function is called, what’s the first thing that Scheme does with the argument list? It evaluates all the arguments.
what approach has worked best for you? Only one objective: pass a code inspection/peer review, with me as the reviewer, without me finding any bugs or having any other criticism, that has me asking you to redo something. Notes: I wasn’t measuring new hires’ ability to finish quickly, and didn’t encourage them to: I wanted … Read more
You can use it as a sort of assertion that an expression has arithmetic type: #define CHECK_ARITHMETIC(x) (+(x)) This will generate a compile-time error if x evaluates to (say) a pointer. That is about the only practical use I can think of.
Use a lookup table: import operator ops = { “+”: operator.add, “-“: operator.sub } # etc. print(ops[“+”](1,1)) # prints 2
ArrayList implements the List Interface. If you look at the Javadoc for List at the contains method you will see that it uses the equals() method to evaluate if two objects are the same.