Can I use ‘ == ‘ to compare two vectors. I tried it and seems to be working fine. But I don’t know whether it will work in more complex situations

The overload of operator == that works on two std::vectors will compare the vector sizes and return false if those are different; if not, it will compare the contents of the vector element-by-element. If operator == is defined for the vector’s element type, then the comparison of vectors through operator == is valid and meaningful. … Read more

Why do these two comparisons have different results?

Because new Byte() creates value type, which are compared by value (by default it will return byte with value 0). And new Byte[0] creates array, which is a reference type and compared by reference (and these two instances of array will have different references). See Value Types and Reference Types article for details.

Pandas DataFrames with NaNs equality comparison

You can use assert_frame_equals with check_names=False (so as not to check the index/columns names), which will raise if they are not equal: In [11]: from pandas.testing import assert_frame_equal In [12]: assert_frame_equal(df, expected, check_names=False) You can wrap this in a function with something like: try: assert_frame_equal(df, expected, check_names=False) return True except AssertionError: return False In more … Read more

Comparing two structs using ==

You need to overload the == and != operators. Add this to your struct: public static bool operator ==(CisSettings c1, CisSettings c2) { return c1.Equals(c2); } public static bool operator !=(CisSettings c1, CisSettings c2) { return !c1.Equals(c2); }

Test for equality to the default value

To avoid boxing for struct / Nullable<T>, I would use: if (EqualityComparer<T>.Default.Equals(value,default(T))) { // do stuff } This supports any T that implement IEquatable<T>, using object.Equals as a backup, and handles null etc (and lifted operators for Nullable<T>) automatically. There is also Comparer<T>.Default which handles comparison tests. This handles T that implement IComparable<T>, falling back … Read more

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