Endianness is about byte address order. Little endian means the lower significant bytes get the lower addresses. Big endian means the other way around. So it’s about the bytes (8-bit chunks) not nibbles (4-bit chunks). Most computers we use (there are a few exceptions) address bytes at the individual address level. Taking the -12 example: … Read more
I’m not usually one to answer my own questions, but I’ve accomplished exactly what I wanted with some simple code: class BinaryReader2 : BinaryReader { public BinaryReader2(System.IO.Stream stream) : base(stream) { } public override int ReadInt32() { var data = base.ReadBytes(4); Array.Reverse(data); return BitConverter.ToInt32(data, 0); } public Int16 ReadInt16() { var data = base.ReadBytes(2); Array.Reverse(data); … Read more
All versions of Windows that you’ll see are little-endian, yes. The NT kernel actually runs on a big-endian architecture even today.
Since you can’t normally address the bits within a byte individually, there’s no concept of “bit endianness” generally.
No, Intel CPUs are little endian: http://en.wikipedia.org/wiki/Endianness
Assuming what you need is a simple byte swap, try something like Unsigned 16 bit conversion: swapped = (num>>8) | (num<<8); Unsigned 32-bit conversion: swapped = ((num>>24)&0xff) | // move byte 3 to byte 0 ((num<<8)&0xff0000) | // move byte 1 to byte 2 ((num>>8)&0xff00) | // move byte 2 to byte 1 ((num<<24)&0xff000000); // … Read more
The answer is in the sys module: >>> import sys >>> sys.byteorder ‘little’ Of course depending on your machine it may return ‘big’. Your method should certainly work too though.
Add a reference to System.Memory nuget and use BinaryPrimitives.ReverseEndianness(). using System.Buffers.Binary; number = BinaryPrimitives.ReverseEndianness(number); It supports both signed and unsigned integers (byte/short/int/long).
Short answer: there isn’t one. Write the number the way you would write it on paper. Long answer: Endianness is never exposed directly in the code unless you really try to get it out (such as using pointer tricks). 0b0111 is 7, it’s the same rules as hex, writing int i = 0xAA77; doesn’t mean … Read more
According to Wikipedia, Floating-point and endianness On some machines, while integers were represented in little-endian form, floating point numbers were represented in big-endian form. Because there are many floating point formats, and a lack of a standard “network” representation, no standard for transferring floating point values has been made. This means that floating point data … Read more