Something like this should do it: Assembly assembly = Assembly.LoadFrom(“Reports.dll”); Stream stream = assembly.GetManifestResourceStream(“Reports.MyReport.rdlc”); reportViewer.LocalReport.LoadReportDefinition(stream);
Here’s example code that should do it: QDirIterator it(“:”, QDirIterator::Subdirectories); while (it.hasNext()) { qDebug() << it.next(); } Link to documentation: http://doc.qt.io/qt-5/qdiriterator.html
You could do this: objcopy –input binary \ –output elf32-i386 \ –binary-architecture i386 my_file.xml myfile.o This produces an object file that you can link into your executable. This file will contain these symbols that you’ll have to declare in your C code to be able to use them 00000550 D _binary_my_file_xml_end 00000550 A _binary_my_file_xml_size 00000000 … Read more
As an alternative to the answer of sfstewman, here’s a small cmake (2.8) function to convert all files in a specific folder to C data and write them in wished output file: # Creates C resources file from files in given directory function(create_resources dir output) # Create empty output file file(WRITE ${output} “”) # Collect … Read more
To create an ImageIcon from an image file within the same jars your code is loaded: new javax.swing.ImageIcon(getClass().getResource(“myimage.jpeg”)) Class.getResource returns a URL of a resource (or null!). ImageIcon has a constructors that load from a URL. To construct a URL for a resource in a jar not on your “classpath”, see the documentation for java.net.JarURLConnection.
Java 9 native implementation: byte[] data = this.getClass().getClassLoader() .getResourceAsStream(“/assets/myAsset.bin”).readAllBytes();
I think that your problem is in the location of the image. You shall place it in your source, and then use it like this: JButton button = new JButton(); try { Image img = ImageIO.read(getClass().getResource(“resources/water.bmp”)); button.setIcon(new ImageIcon(img)); } catch (Exception ex) { System.out.println(ex); } In this example, it is assumed that image is in … Read more
getClass().getResource() uses the class loader to load the resource. This means that the resource must be in the classpath to be loaded. When doing it with Eclipse, everything you put in the source folder is “compiled” by Eclipse: .java files are compiled into .class files that go the the bin directory (by default) other files … Read more
I’d suggest doing it easier. I assume that the resource exists and the file is writable (this might be an issue if we’re speaking about system directories). public void WriteResourceToFile(string resourceName, string fileName) { using(var resource = Assembly.GetExecutingAssembly().GetManifestResourceStream(resourceName)) { using(var file = new FileStream(fileName, FileMode.Create, FileAccess.Write)) { resource.CopyTo(file); } } }
First of all, change this line : image = ImageIO.read(getClass().getClassLoader().getResource(“resources/icon.gif”)); to this : image = ImageIO.read(getClass().getResource(“/resources/icon.gif”)); More info, on as to where lies the difference between the two approaches, can be found on this thread – Different ways of loading a Resource For Eclipse: How to add Images to your Resource Folder in the Project … Read more