Here’s a Python version: from math import radians, cos, sin, asin, sqrt def haversine(lon1, lat1, lon2, lat2): “”” Calculate the great circle distance in kilometers between two points on the earth (specified in decimal degrees) “”” # convert decimal degrees to radians lon1, lat1, lon2, lat2 = map(radians, [lon1, lat1, lon2, lat2]) # haversine formula … Read more
Assuming that you already have a location object with your current location. Location targetLocation = new Location(“”);//provider name is unnecessary targetLocation.setLatitude(0.0d);//your coords of course targetLocation.setLongitude(0.0d); float distanceInMeters = targetLocation.distanceTo(myLocation);
What you’re using is called the haversine formula, which calculates the distance between two points on a sphere as the crow flies. The Google Maps link you provided shows the distance as 2.2 km because it’s not a straight line. Wolfram Alpha is a great resource for doing geographic calculations, and also shows a distance … Read more
Eli, the code you’ve settled on is incorrect. A point near the line on which the segment lies but far off one end of the segment would be incorrectly judged near the segment. Update: The incorrect answer mentioned is no longer the accepted one. Here’s some correct code, in C++. It presumes a class 2D-vector … Read more
TL;DR: use px. The Facts First, it’s extremely important to know that per spec, the CSS px unit does not equal one physical display pixel. This has always been true – even in the 1996 CSS 1 spec. CSS defines the reference pixel, which measures the size of a pixel on a 96 dpi display. … Read more