Script its left and top properties as the number of pixels from the left edge and top edge respectively. It must have position: absolute; var d = document.getElementById(‘yourDivId’); d.style.position = “absolute”; d.style.left = x_pos+’px’; d.style.top = y_pos+’px’; Or do it as a function so you can attach it to an event like onmousedown function placeDiv(x_pos, … Read more
Given li in the question: li = list(zip(range(1, 14), range(14, 27))) To unpack the data from pairs into lists use zip: x, y = zip(*li) x → (1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13) y → (14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26) … Read more
This is a variant on Hank Ditton’s suggestion that should be more efficient time- and memory-wise, especially if you’re selecting relatively few points out of all possible points. The idea is that, whenever a new point is generated, everything within 200 units of it is added to a set of points to exclude, against which … Read more
Not only is x + y + z = 0, but the absolute values of x, y and z are equal to twice the radius of the ring. This should be sufficient to identify every hexagon on each successive ring: var radius = 4; for(var i = 0; i < radius; i++) { for(var j … Read more
Here’s a reusable function you can use. It includes doctests and data validation: def bilinear_interpolation(x, y, points): ”’Interpolate (x,y) from values associated with four points. The four points are a list of four triplets: (x, y, value). The four points can be in any order. They should form a rectangle. >>> bilinear_interpolation(12, 5.5, … [(10, … Read more
In photoshop, the information pannel give you that. I’m pretty sure it’s also possible in Gimp. Or you can make your own tool ! I made you a small example in jsfiddle : http://jsfiddle.net/zz3Rh/19/ The html : <div id=”image”>image</div> coordinates : <div id=”coordinates”>0</div> The css : #image{ height:350px; background:#c00;} The js (with jquery loaded) : … Read more
Have you tried this mathematical formula to change the range of a number? And also instead of storing this: x, y, width, height 433, 343, 1257, 959 331, 823, 1257, 959 You could store it normalized between 0 and 1 so it works for any width/height (calculated by dividing each x by its width and … Read more
Here’s what worked for me, without so much bs. int x = (int) ((MAP_WIDTH/360.0) * (180 + lon)); int y = (int) ((MAP_HEIGHT/180.0) * (90 – lat)); The lat,lon coordinates were given to me by Android devices. So they should be in the same standard used by all Google Earth/Map products.
This is becoming a FAQ. See the replies to these questions: Add “Search Area” outline onto google maps result Google has started highlighting search areas in Pink color. Is this feature available in Google Maps API 3?