Storing lambdas in a dictionary

You cannot use assignments in a expression, and a lambda only takes an expression. You can store lambdas in dictionaries just fine otherwise: dict = {‘Applied_poison_rating_bonus’ : (lambda target, magnitude: target.equipmentPoisonRatingBonus + magnitude)} The above lambda of course only returns the result, it won’t alter target.equimentPoisonRatingBonus in-place.

Each Dictionary entry must have an associated key attribute

Note that Application.Resources requires an instance of ResourceDictionary, so you have to do something like this: <Application.Resources> <ResourceDictionary> <vm:ViewModelLocator x:Key=”Locator” xmlns:vm=”using:Scedule.ViewModel” /> <ResourceDictionary.MergedDictionaries> <ResourceDictionary Source=”Resource Dictionaries/StandardStyles.xaml”/> </ResourceDictionary.MergedDictionaries> </ResourceDictionary> </Application.Resources> So it’s not strange at all, it’s also not a bug. If you want your ResourceDictionary to be treated as a resource, you of course have … Read more

Alternative to dict comprehension prior to Python 2.7

Use: gw_func_dict = dict((chr(2**i), func) for i, func in enumerate(gwfuncs[:8])) That’s the dict() function with a generator expression producing (key, value) pairs. Or, to put it generically, a dict comprehension of the form: {key_expr: value_expr for targets in iterable <additional loops or if expressions>} can always be made compatible with Python < 2.7 by using: … Read more

Accessing map value by index

Your map is not supposed to be accessed that way, it’s indexed by keys not by positions. A map iterator is bidirectional, just like a list, so the function you are using is no more inefficient than accessing a list by position. If you want random access by position then use a vector or a … Read more

Split a dictionary in half?

This would work, although I didn’t test edge-cases: >>> d = {‘key1’: 1, ‘key2’: 2, ‘key3’: 3, ‘key4’: 4, ‘key5’: 5} >>> d1 = dict(d.items()[len(d)/2:]) >>> d2 = dict(d.items()[:len(d)/2]) >>> print d1 {‘key1’: 1, ‘key5’: 5, ‘key4’: 4} >>> print d2 {‘key3’: 3, ‘key2’: 2} In python3: d = {‘key1’: 1, ‘key2’: 2, ‘key3’: 3, … Read more

Argument Exception “Item with Same Key has already been added”

This error is fairly self-explanatory. Dictionary keys are unique and you cannot have more than one of the same key. To fix this, you should modify your code like so: Dictionary<string, string> rct3Features = new Dictionary<string, string>(); Dictionary<string, string> rct4Features = new Dictionary<string, string>(); foreach (string line in rct3Lines) { string[] items = line.Split(new String[] … Read more

Hata!: SQLSTATE[HY000] [1045] Access denied for user 'divattrend_liink'@'localhost' (using password: YES)