How do I sort a dictionary by key?

Note: for Python 3.7+, see this answer Standard Python dictionaries are unordered (until Python 3.7). Even if you sorted the (key,value) pairs, you wouldn’t be able to store them in a dict in a way that would preserve the ordering. The easiest way is to use OrderedDict, which remembers the order in which the elements … Read more

How to directly initialize a HashMap (in a literal way)?

All Versions In case you happen to need just a single entry: There is Collections.singletonMap(“key”, “value”). For Java Version 9 or higher: Yes, this is possible now. In Java 9 a couple of factory methods have been added that simplify the creation of maps : // this works for up to 10 elements: Map<String, String> … Read more

Create a dictionary with comprehension

Use a dict comprehension (Python 2.7 and later): {key: value for (key, value) in iterable} Alternatively for simpler cases or earlier version of Python, use the dict constructor, e.g.: pairs = [(‘a’, 1), (‘b’, 2)] dict(pairs) #=> {‘a’: 1, ‘b’: 2} dict([(k, v+1) for k, v in pairs]) #=> {‘a’: 2, ‘b’: 3} Given separate … Read more

Sort a Map by values

Here’s a generic-friendly version: public class MapUtil { public static <K, V extends Comparable<? super V>> Map<K, V> sortByValue(Map<K, V> map) { List<Entry<K, V>> list = new ArrayList<>(map.entrySet()); list.sort(Entry.comparingByValue()); Map<K, V> result = new LinkedHashMap<>(); for (Entry<K, V> entry : list) { result.put(entry.getKey(), entry.getValue()); } return result; } }

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