In general, there’s no way (in a browser) to serialize objects with functions attached to them: Every function has a reference to its outer scope, that scope won’t exist when you deserialize it, so serialized references to that scope will be invalid. What I would do is use the built-in (or json2.js) JSON.stringify and JSON.parse … Read more
You need to add some annotations on the constructor to tell Jackson how to build the object. The following worked for me: public class AgentResponse<T> { private T result; @JsonCreator public AgentResponse(@JsonProperty(“result”) T result) { this.result = result; } public T getResult() { return result; } } Without the @JsonCreator annotation, Jackson cannot know to … Read more
There is a feature and an annotation exactly fitting this purpose. I tested and it works with UUIDs like in your example: class MyUUIDClass { public int knownField; Map<String, UUID> unknownFields = new HashMap<>(); // Capture all other fields that Jackson do not match other members @JsonAnyGetter public Map<String, UUID> otherFields() { return unknownFields; } … Read more
There are multiple ways; before version 1.8, simplest way is probably to do: @JsonDeserialize(as=Cat.class) public abstract class AbstractAnimal { … } as to deciding based on attribute, that is best done using @JsonTypeInfo, which does automatic embeddeding (when writing) and use of type information. There are multiple kinds of type info (class name, logical type … Read more
Ended up creating a converter: public class BoolConverter : JsonConverter { public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer) { writer.WriteValue(((bool)value) ? 1 : 0); } public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer) { return reader.Value.ToString() == “1”; } public override bool CanConvert(Type objectType) { return objectType == typeof(bool); } … Read more
Simply take off the Namespace =: [XmlRoot(“register-account”), XmlType(“register-account”)] public class RegisterAccountResponse {…} since your xml doesn’t seem to be in an xml-namespace. Also, [Serializable] isn’t used by XmlSerializer. If your xml was using a namespace it would have an xmlns at the root. Also, to help with callers you could add where T : class, … Read more
You can do this using Jackson: mapper.readerForUpdating(object).readValue(json); See also Merging Two JSON Documents Using Jackson
Here’s a solution I’ve come up with that expands a bit on Erik Gillespie’s. It does exactly what you asked for and it worked for me. Using Jackson 2.9 @JsonDeserialize(using = CustomDeserializer.class) public abstract class BaseClass { private String commonProp; } // Important to override the base class’ usage of CustomDeserializer which produces an infinite … Read more
Try casting the custom object to FooObject: $foo = [FooObject](Get-Content ‘C:\path\to\your.json’ | Out-String | ConvertFrom-Json) If that doesn’t work, try constructing the FooObject instance with the properties of the input object (provided the class has a constructor like that): $json = Get-Content ‘C:\path\to\your.json’ | Out-String | ConvertFrom-Json $foo = New-Object FooObject ($json.Foo, $json.Bar, $json.Baz) If … Read more
If you just want a generic method that can handle any arbitrary JSON and convert it into a nested structure of regular .NET types (primitives, Lists and Dictionaries), you can use JSON.Net’s LINQ-to-JSON API to do it: using System.Linq; using Newtonsoft.Json.Linq; public static class JsonHelper { public static object Deserialize(string json) { return ToObject(JToken.Parse(json)); } … Read more