Take a look at the PrettyTime library. It’s quite simple to use: import org.ocpsoft.prettytime.PrettyTime; PrettyTime p = new PrettyTime(); System.out.println(p.format(new Date())); // prints “moments ago” You can also pass in a locale for internationalized messages: PrettyTime p = new PrettyTime(new Locale(“fr”)); System.out.println(p.format(new Date())); // prints “à l’instant” As noted in the comments, Android has this … Read more
The definition of “the number of months in the difference” is subject to a lot of interpretation. 🙂 You can get the year, month, and day of month from a JavaScript date object. Depending on what information you’re looking for, you can use those to figure out how many months are between two points in … Read more
if you want to compute differences between two known dates, use total_seconds like this: import datetime as dt a = dt.datetime(2013,12,30,23,59,59) b = dt.datetime(2013,12,31,23,59,59) (b-a).total_seconds() 86400.0 #note that seconds doesn’t give you what you want: (b-a).seconds 0
I suggest to use DateTime and DateInterval objects. $date1 = new DateTime(“2007-03-24”); $date2 = new DateTime(“2009-06-26”); $interval = $date1->diff($date2); echo “difference ” . $interval->y . ” years, ” . $interval->m.” months, “.$interval->d.” days “; // shows the total amount of days (not divided into years, months and days like above) echo “difference ” . $interval->days … Read more
Jeff, your code is nice but could be clearer with constants (as suggested in Code Complete). const int SECOND = 1; const int MINUTE = 60 * SECOND; const int HOUR = 60 * MINUTE; const int DAY = 24 * HOUR; const int MONTH = 30 * DAY; var ts = new TimeSpan(DateTime.UtcNow.Ticks – … Read more