Performance Counters – Process – % Processor Time. Little sample code to give you the idea: using System; using System.Diagnostics; using System.Threading; namespace StackOverflow { class Program { static void Main(string[] args) { PerformanceCounter myAppCpu = new PerformanceCounter( “Process”, “% Processor Time”, “OUTLOOK”, true); Console.WriteLine(“Press the any key to stop…\n”); while (!Console.KeyAvailable) { double pct … Read more
The first iteration of the counter will always be 0, because it has nothing to compare to the last value. Try this: var cpuload = new PerformanceCounter(“Processor”, “% Processor Time”, “_Total”); Console.WriteLine(cpuload.NextValue() + “%”); Console.WriteLine(cpuload.NextValue() + “%”); Console.WriteLine(cpuload.NextValue() + “%”); Console.WriteLine(cpuload.NextValue() + “%”); Console.WriteLine(cpuload.NextValue() + “%”); Then you should see some data coming out. It’s … Read more
Try to calculate nth prime number to simulate CPU intensive work – public void Slow() { long nthPrime = FindPrimeNumber(1000); //set higher value for more time } public long FindPrimeNumber(int n) { int count=0; long a = 2; while(count<n) { long b = 2; int prime = 1;// to check if found a prime while(b … Read more
First off, you have to understand that CPU usage is always an average over a certain time. At any given time, the CPU is either working or it is not. The CPU is never 40% working. We can, however, simulate a 40% load over say a second by having the CPU work for 0.4 seconds … Read more
I have been struggling with the same issue for a couple of days on Visual Studio 2013 Update 4. Disabling “Enable Browser Link” option in here: Fixed the issue for me.
Rate returns a per second value, so multiplying by 100 will give a percentage: rate(container_cpu_user_seconds_total[30s]) * 100
Update. This code is working for me: Update 2. The thread_list was leaking, so added vm_deallocate #import <mach/mach.h> #import <assert.h> float cpu_usage() { kern_return_t kr; task_info_data_t tinfo; mach_msg_type_number_t task_info_count; task_info_count = TASK_INFO_MAX; kr = task_info(mach_task_self(), TASK_BASIC_INFO, (task_info_t)tinfo, &task_info_count); if (kr != KERN_SUCCESS) { return -1; } task_basic_info_t basic_info; thread_array_t thread_list; mach_msg_type_number_t thread_count; thread_info_data_t thinfo; mach_msg_type_number_t … Read more
cat /proc/stat http://www.linuxhowtos.org/System/procstat.htm I agree with this answer above. The cpu line in this file gives the total number of “jiffies” your system has spent doing different types of processing. What you need to do is take 2 readings of this file, seperated by whatever interval of time you require. The numbers are increasing values … Read more
Update. This code is working for me: Update 2. The thread_list was leaking, so added vm_deallocate #import <mach/mach.h> #import <assert.h> float cpu_usage() { kern_return_t kr; task_info_data_t tinfo; mach_msg_type_number_t task_info_count; task_info_count = TASK_INFO_MAX; kr = task_info(mach_task_self(), TASK_BASIC_INFO, (task_info_t)tinfo, &task_info_count); if (kr != KERN_SUCCESS) { return -1; } task_basic_info_t basic_info; thread_array_t thread_list; mach_msg_type_number_t thread_count; thread_info_data_t thinfo; mach_msg_type_number_t … Read more
You can get this from docker stats e.g: $ docker stats –no-stream CONTAINER CPU % MEM USAGE / LIMIT MEM % NET I/O BLOCK I/O PIDS 6b5c0fcfa7d4 0.13% 2.203 MiB / 4 MiB 55.08% 5.223 kB / 648 B 102.4 kB / 876.5 kB 3