Inline conditions in Lua (a == b ? “yes” : “no”)?
Sure: print(“blah: ” .. (a and “blah” or “nahblah”))
Sure: print(“blah: ” .. (a and “blah” or “nahblah”))
>>> import numpy as np >>> a = np.random.randint(0, 5, size=(5, 4)) >>> a array([[4, 2, 1, 1], [3, 0, 1, 2], [2, 0, 1, 1], [4, 0, 2, 3], [0, 0, 0, 2]]) >>> b = a < 3 >>> b array([[False, True, True, True], [False, True, True, True], [ True, True, True, True], … Read more
if i.between?(1, 10) do thing 1 elsif i.between?(11,20) do thing 2 …
To formalize some of the approaches laid out above: Create a function that operates on the rows of your dataframe like so: def f(row): if row[‘A’] == row[‘B’]: val = 0 elif row[‘A’] > row[‘B’]: val = 1 else: val = -1 return val Then apply it to your dataframe passing in the axis=1 option: … Read more
You can simply use != instead.
Answering in generalities: Yes, usually. See More Info Here Yes, because each has a different JS processing engine, however, in running a test on the site below, the switch always out performed the if, elseif on a large number of iterations. Test site
my.data.frame <- subset(data , V1 > 2 | V2 < 4) An alternative solution that mimics the behavior of this function and would be more appropriate for inclusion within a function body: new.data <- data[ which( data$V1 > 2 | data$V2 < 4) , ] Some people criticize the use of which as not needed, … Read more
You had it right, just put a space between the ! and the [[ like if ! [[
The no-op command in shell is : (colon). if [ “$a” -ge 10 ] then : elif [ “$a” -le 5 ] then echo “1” else echo “2” fi From the bash manual: : (a colon) Do nothing beyond expanding arguments and performing redirections. The return status is zero.
The bug is probably somewhere else in your code, because it should work fine: >>> 3 not in [2, 3, 4] False >>> 3 not in [4, 5, 6] True Or with tuples: >>> (2, 3) not in [(2, 3), (5, 6), (9, 1)] False >>> (2, 3) not in [(2, 7), (7, 3), “hi”] … Read more