Checking the equality of two slices

You should use reflect.DeepEqual() DeepEqual is a recursive relaxation of Go’s == operator. DeepEqual reports whether x and y are “deeply equal,” defined as follows. Two values of identical type are deeply equal if one of the following cases applies. Values of distinct types are never deeply equal. Array values are deeply equal when their … Read more

Comparing two strings, ignoring case in C# [duplicate]

If you’re looking for efficiency, use this: string.Equals(val, “astringvalue”, StringComparison.OrdinalIgnoreCase) Ordinal comparisons can be significantly faster than culture-aware comparisons. ToLowerCase can be the better option if you’re doing a lot of comparisons against the same string, however. As with any performance optimization: measure it, then decide!

How to compare dates in Java? [duplicate]

Date has before and after methods and can be compared to each other as follows: if(todayDate.after(historyDate) && todayDate.before(futureDate)) { // In between } For an inclusive comparison: if(!historyDate.after(todayDate) && !futureDate.before(todayDate)) { /* historyDate <= todayDate <= futureDate */ } You could also give Joda-Time a go, but note that: Joda-Time is the de facto standard … Read more

Image comparison – fast algorithm

Below are three approaches to solving this problem (and there are many others). The first is a standard approach in computer vision, keypoint matching. This may require some background knowledge to implement, and can be slow. The second method uses only elementary image processing, and is potentially faster than the first approach, and is straightforward … Read more

Optimum way to compare strings in JavaScript? [duplicate]

You can use the localeCompare() method. string_a.localeCompare(string_b); /* Expected Returns: 0: exact match -1: string_a < string_b 1: string_a > string_b */ Further Reading: MDN: String.prototype.localeCompare Stack Overflow – Is there a JavaScript strcmp()? Tutorials Point: JavaScript String – localeCompare() Method

Check if all elements in a list are identical

Use itertools.groupby (see the itertools recipes): from itertools import groupby def all_equal(iterable): g = groupby(iterable) return next(g, True) and not next(g, False) or without groupby: def all_equal(iterator): iterator = iter(iterator) try: first = next(iterator) except StopIteration: return True return all(first == x for x in iterator) There are a number of alternative one-liners you might … Read more

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