You are asking several questions at once. Let me address them separately: How similar Java and C#? Both C# and Java drew from C/C++ (and Objective C, and others) to define their syntax. And both of them are compiled to an intermediate language. This common origin makes the languages look similar in many levels, to … Read more
The following Java libraries offer multiple compare algorithms (Levenshtein,Jaro Winkler,…): Apache Commons Lang 3: https://commons.apache.org/proper/commons-lang/ Simmetrics: http://sourceforge.net/projects/simmetrics/ Both libraries have a java documentation (Apache Commons Lang Javadoc,Simmetrics Javadoc). //Usage of Apache Commons Lang 3 import org.apache.commons.lang3.StringUtils; public double compareStrings(String stringA, String stringB) { return StringUtils.getJaroWinklerDistance(stringA, stringB); } //Usage of Simmetrics import uk.ac.shef.wit.simmetrics.similaritymetrics.JaroWinkler public double compareStrings(String … Read more
You can do that directly in Twig now: {% if ‘World’ starts with ‘F’ %} {% endif %} “Ends with” is also supported: {% if ‘Hello’ ends with ‘n’ %} {% endif %} Other handy keywords also exist: Complex string comparisons: {% if phone matches ‘{^[\\d\\.]+$}’ %} {% endif %} (Note: double backslashes are converted … Read more
I agree this is confusing. Should().BeEquivalentTo() should actually be called Should().EqualInAnyOrder() or something like that. As you said, it uses the Equals implementation of the involved objects to see if all of the ones in the expected collection appear in the actual collection, regardless of order. I’ll need to fix that for the next major … Read more
I am not sure what exactly you are looking for, so let me first give complete equality and then key equality. Maybe the latter fits your needs already. Complete Equality (While standard equivalence can be tested using std::map‘s own comparison operators, the following can be used as a base for a comparison on a per-value … Read more
Java 7.0 added a new handy class: Objects. It has a method exactly for this: Objects.equals(Object a, Object b)
Simply use : mapA.equals(mapB); Compares the specified object with this map for equality. Returns true if the given object is also a map and the two maps represent the same mappings
KennyTM is correct, there is no other simpler or more efficient way. However, if you have many variables, you could also build an array of the values and use the IEnumerable.All method to verify they’re all 1. More readable, IMO. if (new[] { v1, v2, v3, v4, v5, v6, v7, v8, v9, v10 }.All(x => … Read more
Edit 8-31-12: per Joey’s comment below, be mindful of the format of the bitmaps you compare. They may contain padding on the strides that render the bitmaps unequal, despite being equivalent pixel-wise. See this question for more details. Reading this answer to a question regarding comparing byte arrays has yielded a MUCH FASTER method: using … Read more
You can’t accidently assign null to obj by typing obj = null instead. However, that’s a reminiscence from C times, in java, it is not possible, as the = expression returns the right hand side of the assignment. As null is not a boolean, the compiler will complain. I would try to explain it to … Read more