For those who want a “standard” text formatting of the hash, you can use something like the following: static string Hash(string input) { using (SHA1Managed sha1 = new SHA1Managed()) { var hash = sha1.ComputeHash(Encoding.UTF8.GetBytes(input)); var sb = new StringBuilder(hash.Length * 2); foreach (byte b in hash) { // can be “x2” if you want lowercase … Read more
A byte is always signed in Java. You may get its unsigned value by binary-anding it with 0xFF, though: int i = 234; byte b = (byte) i; System.out.println(b); // -22 int i2 = b & 0xFF; System.out.println(i2); // 234
You can use encoding/binary’s ByteOrder to do this for 16, 32, 64 bit types Play package main import “fmt” import “encoding/binary” func main() { var mySlice = []byte{244, 244, 244, 244, 244, 244, 244, 244} data := binary.BigEndian.Uint64(mySlice) fmt.Println(data) }
You need to seek back to the beginning of the file after writing the initial in memory file… myio.seek(0)
Use Integer#toBinaryString(): byte b1 = (byte) 129; String s1 = String.format(“%8s”, Integer.toBinaryString(b1 & 0xFF)).replace(‘ ‘, ‘0’); System.out.println(s1); // 10000001 byte b2 = (byte) 2; String s2 = String.format(“%8s”, Integer.toBinaryString(b2 & 0xFF)).replace(‘ ‘, ‘0’); System.out.println(s2); // 00000010 DEMO.
It sets result to the (unsigned) value resulting from putting the 8 bits of value in the lowest 8 bits of result. The reason something like this is necessary is that byte is a signed type in Java. If you just wrote: int result = value; then result would end up with the value ff … Read more
result = bytes.fromhex(some_hex_string)
Byte: Today, a byte is almost always 8 bit. However, that wasn’t always the case and there’s no “standard” or something that dictates this. Since 8 bits is a convenient number to work with it became the de facto standard. Word: The natural size with which a processor is handling data (the register size). The … Read more
You are writing to your memory stream twice, also you are not disposing the stream after use. You are also asking the image decoder to apply embedded color correction. Try this instead: using (var ms = new MemoryStream(byteArrayIn)) { return Image.FromStream(ms); }
Constants are evaluated as ints, so 2147483647 + 1 overflows and gives you a new int, which is assignable to int, while 127 + 1 also evaluated as int equals to 128, and it is not assignable to byte.