private int getIntFromBitArray(BitArray bitArray) { if (bitArray.Length > 32) throw new ArgumentException(“Argument length shall be at most 32 bits.”); int[] array = new int[1]; bitArray.CopyTo(array, 0); return array[0]; }
If you have an image img (which is a numpy array) you can convert it into string using: >>> img_str = cv2.imencode(‘.jpg’, img)[1].tostring() >>> type(img_str) ‘str’ Now you can easily store the image inside your database, and then recover it by using: >>> nparr = np.fromstring(STRING_FROM_DATABASE, np.uint8) >>> img = cv2.imdecode(nparr, cv2.CV_LOAD_IMAGE_COLOR) where you need … Read more
The struct module does only support fixed-length structures. For variable-length strings, your options are either: Dynamically construct your format string (a str will have to be converted to a bytes before passing it to pack()): s = bytes(s, ‘utf-8’) # Or other appropriate encoding struct.pack(“I%ds” % (len(s),), len(s), s) Skip struct and just use normal … Read more
Yes, there is. It’s the normal mode command go. From :h go: [count]go Go to {count} byte in the buffer. For example, 42go jumps to byte 42. In order to jump to a hexadecimal or octal address you would need to construct a command with :normal! go or the equivalent :goto, and the str2nr() … Read more
Take a look at the PNG spec. This format has some very good rationale behind it. Also, decide what’s important for your future format: compactness, compatibility, allowing to embed other formats (different compression algorithms) inside it. Another interesting example would be the Google’s protocol buffers, where size of the transferred data is the king. As … Read more
printf() doesn’t directly support that. Instead you have to make your own function. Something like: while (n) { if (n & 1) printf(“1”); else printf(“0”); n >>= 1; } printf(“\n”);
You could use a Regex to check that it is “^[01]+$” (or better, “^[01]{1,32}$”), and then use Convert? of course, exceptions are unlikely to be a huge problem anyway! Inelegant? maybe. But they work. Example (formatted for vertical space): static readonly Regex binary = new Regex(“^[01]{1,32}$”, RegexOptions.Compiled); static void Main() { Test(“”); Test(“01101”); Test(“123”); Test(“0110101101010110101010101010001010100011010100101010”); … Read more
I am not sure if this would help but try to change the b variable to the bytes variable in the line below at least you would be able to view the file in a test editor fs.writeFile(“test.txt”, b, “binary”,function(err) { }); If you would like to have the numbers space separated try the code … Read more
There’s no guaranteed way, but here are a couple of possibilities: Look for a header on the file. Unfortunately, headers are file-specific, so while you might be able to find out that it’s a RAR file, you won’t get the more generic answer of whether it’s text or binary. Count the number of character vs. … Read more
The usual way is to use String#getBytes() to get the underlying bytes and then present those bytes in some other form (hex, binary whatever). Note that getBytes() uses the default charset, so if you want the string converted to some specific character encoding, you should use getBytes(String encoding) instead, but many times (esp when dealing … Read more