The manpage for bash v3.2.48 says: […] The format for arithmetic expansion is: $((expression)) The old format $[expression] is deprecated and will be removed in upcoming versions of bash. So $[…] is old syntax that should not be used anymore.
== is reflexive for all numbers, zero, -zero, ininity, and -infinity, but not for nan. You can get inf, -inf, and nan in native Python just by arithmetic operations on literals, like below. These behave correctly, as in IEEE 754 and without math domain exception: >>> 1e1000 == 1e1000 True >>> 1e1000/1e1000 == 1e1000/1e1000 False … Read more
I think the above answer deserves a few words of explanation here nevertheless. A short note in advance: Arithmetic expressions in Prolog are just terms (“Everything is a term in Prolog”), which are not evaluated automatically. (If you have a Lisp background, think of quoted lists). So 3 + 4 is just the same as … Read more
TL;DR: as is the most common way to convert between the primitive numeric types but using it requires thinking. fn c_to_f(c: f32) -> f32 { (c * (9 as f32 / 5 as f32)) + 32 as f32 } In this example though, it’s more reasonable to just use floating point literals to start with: … Read more
OK, to be clear. Twisted doesn’t do anything about cpu bound tasks and for good reason. there’s no way to make a compute bound job go any quicker by reordering subtasks; the only thing you could possibly do is add more compute resources; and even that wouldn’t work out in python because of a subtlety … Read more
The + is interpreted as an unary plus operator. It simply returns the promoted value of its operand.
There are a number of ways to implement your arithmetic test using bitwise arithmetic. Your expression: x == 0 || x == 1 is logically equivalent to each one of these: (x & 1) == x (x & ~1) == 0 (x | 1) == 1 (~x | 1) == (uint)-1 x >> 1 == … Read more
Try the following: for i in {1..600}; do echo wget http://example.com/search/link$(($i % 5)); done The $(( )) syntax does an arithmetic evaluation of the contents.
The C# language doesn’t have a power operator. However, the .NET Framework offers the Math.Pow method: Returns a specified number raised to the specified power. So your example would look like this: float Result, Number1, Number2; Number1 = 2; Number2 = 2; Result = Math.Pow(Number1, Number2);