Finding the indices of matching elements in list in Python

You are using .index() which will only find the first occurrence of your value in the list. So if you have a value 1.0 at index 2, and at index 9, then .index(1.0) will always return 2, no matter how many times 1.0 occurs in the list.

Use enumerate() to add indices to your loop instead:

def find(lst, a, b):
    result = []
    for i, x in enumerate(lst):
        if x<a or x>b:
            result.append(i)
    return result

You can collapse this into a list comprehension:

def find(lst, a, b):
    return [i for i, x in enumerate(lst) if x<a or x>b]