To complete Gunter’s answer: the recommended way to compare lists for equality (rather than identity) is by using the Equality classes from the following package import ‘package:collection/collection.dart’; Edit: prior to 1.13, it was import ‘package:collection/equality.dart’; E.g.: Function eq = const ListEquality().equals; print(eq([1,’two’,3], [1,’two’,3])); // => true The above prints true because the corresponding list elements … Read more
In Kotlin, there’s no way to check the generic parameters at runtime in general case (like just checking the items of a List<T>, which is only a special case), so casting a generic type to another with different generic parameters will raise a warning unless the cast lies within variance bounds. There are different solutions, … Read more
Once again, it seems I’ve answered my own question by getting impatient and asking it in #clojure on Freenode. Good thing answering your own questions is encouraged on Stackoverflow.com 😀 I had a quick discussion with Rich Hickey, and here is the gist of it. [12:21] <Raynes> Vectors aren’t seqs, right? [12:21] <rhickey> Raynes: no, … Read more
Like this: xy.list <- split(xy.df, seq(nrow(xy.df))) And if you want the rownames of xy.df to be the names of the output list, you can do: xy.list <- setNames(split(xy.df, seq(nrow(xy.df))), rownames(xy.df))
Operators like <= in Python are generally not overriden to mean something significantly different than “less than or equal to”. It’s unusual for the standard library does this–it smells like legacy API to me. Use the equivalent and more clearly-named method, set.issubset. Note that you don’t need to convert the argument to a set; it’ll … Read more
You can use: var newList = new List.from(list1)..addAll(list2); If you have several lists you can use: var newList = [list1, list2, list3].expand((x) => x).toList() As of Dart 2 you can now use +: var newList = list1 + list2 + list3; As of Dart 2.3 you can use the spread operator: var newList = […list1, … Read more
Short answer: use not set(a).isdisjoint(b), it’s generally the fastest. There are four common ways to test if two lists a and b share any items. The first option is to convert both to sets and check their intersection, as such: bool(set(a) & set(b)) Because sets are stored using a hash table in Python, searching them … Read more
You can pass a comparison function to List.sort. someObjects.sort((a, b) => a.someProperty.compareTo(b.someProperty));
If the aim is to run a sequence of shell commands, you may be able to achieve this as follows: # note: no dash before commands some_stuff: &some_stuff |- a b c combined_stuff: – *some_stuff – d – e – f This is equivalent to: some_stuff: “a\nb\nc” combined_stuff: – “a\nb\nc” – d – e – … Read more
This works fine. val selectedSeries = series.toMutableList()