Seem’s like I found what to do. If you pass not the maps of maps but the list of maps you can use such code resource “google_compute_instance” “node” { for_each = {for vm in var.vms: vm.hostname => vm} name = “${each.value.hostname}” machine_type = “custom-${each.value.cpu}-${each.value.ram*1024}” zone = “${var.gcp_zone}” boot_disk { initialize_params { image = “${var.image_name}” size … Read more
attrs = [o.attr for o in objs] was the right code for making a list like the one you describe. Don’t try to subclass list for this. Is there something you did not like about that snippet?
You can simply convert the List using Scala’s JavaConverters: import scala.collection.JavaConverters._ def findAllQuestion():List[Question] = { questionDao.getAllQuestions().asScala.toList }
length(x) Get or set the length of vectors (including lists) and factors, and of any other R object for which a method has been defined. lengths(x) Get the length of each element of a list or atomic vector (is.atomic) as an integer or numeric vector.
listOf top-level function to the rescue: val geeks = listOf(“Fowler”, “Beck”, “Evans”)
You can grow them row by row by appending or using rbind(). That does not mean you should. Dynamically growing structures is one of the least efficient ways to code in R. If you can, allocate your entire data.frame up front: N <- 1e4 # total number of rows to preallocate–possibly an overestimate DF <- … Read more
I think you’re looking for grouped. It returns an iterator, but you can convert the result to a list, scala> List(1,2,3,4,5,6,”seven”).grouped(4).toList res0: List[List[Any]] = List(List(1, 2, 3, 4), List(5, 6, seven))
Technically lists are vectors, although very few would use that term. “list” is one of several modes, with others being “logical”, “character”, “numeric”, “integer”. What you are calling vectors are “atomic vectors” in strict R parlance: aaa <- vector(“list”, 3) is.list(aaa) #TRUE is.vector(aaa) #TRUE Lists are a “recursive” type (of vector) whereas atomic vectors are … Read more
Use toSet and then toList var ids = [1, 4, 4, 4, 5, 6, 6]; var distinctIds = ids.toSet().toList(); Result: [1, 4, 5, 6] Or with spread operators: var distinctIds = […{…ids}];
Yes, there is: Prelude> import Data.List Prelude Data.List> intercalate ” ” [“is”,”there”,”such”,”a”,”function”,”?”] “is there such a function ?” intersperse is a bit more general: Prelude> import Data.List Prelude Data.List> concat (intersperse ” ” [“is”,”there”,”such”,”a”,”function”,”?”]) “is there such a function ?” Also, for the specific case where you want to join with a space character, there … Read more