Need to remove from the xml
Try adding the omit-xml-declaration=”yes” attribute to your xsl:output tag. It should then read like this: <xsl:output method=”xml” indent=”yes” omit-xml-declaration=”yes” />
xslt
Using XSLT to copy all nodes in XML, with support for special cases
<?xml version=”1.0″?> <xsl:stylesheet version=”1.0″ xmlns:xsl=”http://www.w3.org/1999/XSL/Transform”> <!–Identity template, provides default behavior that copies all content into the output –> <xsl:template match=”@*|node()”> <xsl:copy> <xsl:apply-templates select=”@*|node()”/> </xsl:copy> </xsl:template> <!–More specific template for Node766 that provides custom behavior –> <xsl:template match=”Node766″> <xsl:copy> <xsl:apply-templates select=”@*|node()”/> <!–Do something special for Node766, like add a certain string–> <xsl:text> add some text </xsl:text> … Read more
How to check if an attribute exists in a XML file using XSL
Here is a very simple way to do conditional processing using the full power of XSLT pattern matching and exclusively “push” style, and this even avoids the need to use conditional instructions such as <xsl:if> or <xsl:choose>: <xsl:stylesheet version=”1.0″ xmlns:xsl=”http://www.w3.org/1999/XSL/Transform”> <xsl:output omit-xml-declaration=”yes” indent=”yes”/> <xsl:template match=”/root/diagram[graph[1]/@color]”> Graph[1] has color </xsl:template> <xsl:template match=”/root/diagram[not(graph[1]/@color)]”> Graph[1] has not color … Read more
Passing parameters to XSLT Stylesheet via .NET
You need to define the parameter within your XSLT and you also need to pass the XsltArgumentList as an argument to the Transform call: private static void CreateHierarchy(string manID) { string man_ID = manID; XsltArgumentList argsList = new XsltArgumentList(); argsList.AddParam(“Boss_ID”, “”, man_ID); XslCompiledTransform transform = new XslCompiledTransform(true); transform.Load(“htransform.xslt”); using (StreamWriter sw = new StreamWriter(“output.xml”)) { … Read more
Which version of XPATH and XSLT am I using..?
In XSLT, call system-property(‘xsl:version’). It will return 1.0 or 2.0 depending on whether you are using a 1.0 or 2.0 processor. In XPath, there’s no direct equivalent. But a quick test is to call current-date() with no arguments. If this succeeds, you have a 2.0 processor, if it fails, you have a 1.0 processor. Unless … Read more
Performance: call-template vs apply-template
As with all performance questions, the answer will depend on your particular configuration (in particular the XSLT processor you’re using) and the kind of processing that you’re doing. <xsl:apply-templates> takes a sequence of nodes and goes through them one by one. For each, it locates the template with the highest priority that matches the node, … Read more
How can I select the first element using XSLT?
If you wish to output XHTML 1.1, here’s one way: <?xml version=”1.0″?> <xsl:transform version=”2.0″ xmlns:xsl=”http://www.w3.org/1999/XSL/Transform” xmlns:xs=”http://www.w3.org/2001/XMLSchema” exclude-result-prefixes=”xsl xs”> <xsl:output mode=”xhtml” version=”1.1″ omit-xml-declaration=”yes” encoding=”utf-8″ media-type=”application/xhtml+xml” indent=”no” doctype-public=”-//W3C//DTD XHTML 1.1//EN” doctype-system=”http://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd” /> <xsl:template match=”//newsItem[1]”> <div><xsl:value-of select=”dateCreated”/></div> <div><xsl:value-of select=”summary”/></div> </xsl:template> </xsl:transform>
How to display in XML output
Unless your XML has a DTD which says what means, you cannot use . The only reason this works in HTML is because the XHTML DTD defines what it means (for XHTML) or it’s just baked in to the parser (HTML). In general you should not use named character entities in XML because such … Read more
Increment a value in XSLT
XSLT is a functional language and among other things this means that variables in XSLT are immutable and once they have been defined their value cannot be changed. Here is how the same effect can be achieved in XSLT: <xsl:stylesheet version=”1.0″ xmlns:xsl=”http://www.w3.org/1999/XSL/Transform”> <xsl:output omit-xml-declaration=”yes” indent=”yes”/> <xsl:strip-space elements=”*”/> <xsl:template match=”https://stackoverflow.com/”> <posts> <xsl:for-each select=”data/posts/entry”> <xsl:variable name=”i” select=”position()” … Read more
How do you create a PDF from XML in Java?
A – Explanation You should use Apache FOP framework to generate pdf output. Simply you provide data in xml format and render the page with an xsl-fo file and specify the parameters like margin, page layout in this xsl-fo file. I’ll provide a simple demo, I use maven build tool to gather the needed jar … Read more