Just adding isExpanded:true to the DropdownButton Widget example() { return DropdownButton( isExpanded: true, items: const [ DropdownMenuItem(child: Text(“Abc”)), DropdownMenuItem(child: Text(“Xyz”)), ], hint: const Text(“Select City”), onChanged: null ); }
To get the size/position of a widget on screen, you can use GlobalKey to get its BuildContext to then find the RenderBox of that specific widget, which will contain its global position and rendered size. There is just one thing to be careful of: That context may not exist if the widget is not rendered. … Read more
When considering a JavaScript library/framework for usage you should first define on your goals. I used to separate all JavaScript libraries/frameworks into three categories by their purpose and architecture: I want to pimp up my page with some really “cool” features. Go for JavaScript library. jQuery ZenoUI old: Prototype, Mootools I want to build an … Read more
In Qt 5.2 it is possible to do the following: QSizePolicy sp_retain = widget->sizePolicy(); sp_retain.setRetainSizeWhenHidden(true); widget->setSizePolicy(sp_retain); I earlier posted the same solution here: How to make a Qt widget invisible without changing the position of the other Qt widgets? (which seems to be a duplicate of this question).
You can declare an attribute on your ModelForm class, called formfield_callback. This should be a function which takes a Django model Field instance as an argument, and returns a form Field instance to represent it in the form. Then all you have to do is look to see if the model field passed in is … Read more
You can use the setText() method. Example: import android.widget.Button; Button p1_button = (Button)findViewById(R.id.Player1); p1_button.setText(“Some text”); Also, just as a point of reference, Button extends TextView, hence why you can use setText() just like with an ordinary TextView.
I started with doing everything hand-coded, and of late have been switching to using Qt Designer for most forms. Here are some benefits for each position: Using Qt Designer The biggest time saver for me is managing complex layouts; it saves a lot of tedious coding. Simply (very roughly) arrange your widgets, select them, right-click, … Read more
This will set your tab colors: public static void setTabColor(TabHost tabhost) { for(int i=0;i<tabhost.getTabWidget().getChildCount();i++) { tabhost.getTabWidget().getChildAt(i).setBackgroundColor(Color.parseColor(“#FF0000”)); //unselected } tabhost.getTabWidget().getChildAt(tabhost.getCurrentTab()).setBackgroundColor(Color.parseColor(“#0000FF”)); // selected } and if you put it within the onTabChangedListener(), it will keep the correct color for selected tabs.
As the OP mentioned in an edit, this isn’t currently possible because Flutter uses a custom rendering engine. Widgets are quite limited in what they can render; the documentation explains that only certain layouts may be used. You could theoretically use Flutter’s software renderer to render to an image in a seperate instance from the … Read more
If your widget have no child widgets that depend on it i think you can use: layout.removeWidget(self.widget_name) self.widget_name.deleteLater() self.widget_name = None in my tests when it is a widget that have childs you have to: import sip layout.removeWidget(self.widget_name) sip.delete(self.widget_name) self.widget_name = None if you don’t have a variable name for the widget at class or … Read more