If you dont want a random number, but an UUID with numbers only use: String lUUID = String.format(“%040d”, new BigInteger(UUID.randomUUID().toString().replace(“-“, “”), 16)); in this case left padded to 40 zeros… results for: UUID : b55081fa-9cd1-48c2-95d4-efe2db322a54 in: UUID : 0241008287272164729465721528295504357972
Extending Mike Lively’s answer with a code sample & referring to Oracle too. I had this problem with the OracleDialect (Oracle10gDialect). Adding an annotation @Type to the UUID field fixed it for me. @Id @Type(type=”uuid-char”) private UUID id; Note: also used a TwoWayStringBridge on this field, using the @FieldBridge annotation. Note: type=”uuid-binary” did not work; … Read more
UUID generation is random, but random with bad entropy means that you will end up with easy to guess UUIDs. If you use a good random number generator, you can generate UUIDs that can be used for sessions. The catch to this, however, is that UUIDs don’t have built-in re-play prevention, tampering, fixation, etc., you … Read more
if you read the RFC that defines UUIDs, and which is linked to from the API docs, you’ll see that not all bits of the UUID are actually random (the “variant” and the “version” are not random). so a type 4 UUID (the kind that you intend to use), if implemented correctly, should have 122 … Read more
You can use the TimeUUID type in Cassandra, which backs a Type 1 UUID. This uses the current time and the creator’s MAC address and a sequence number. If the TimeUUID number is generated correctly this can be done with zero collisions (you can use the CQL now() method or insert your own, the java … Read more
Convert the underlying bytes to a base64 value, stripping the = padding and the newline. You probably want to use the base64.urlsafe_b64encode() function to avoid using / and + (_ and – are used instead), so the resulting string can be used as a URL path element: >>> import uuid, base64 >>> base64.urlsafe_b64encode(uuid.uuid1().bytes).rstrip(b’=’).decode(‘ascii’) ’81CMD_bOEeGbPwAjMtYnhg’ The … Read more
You could use UUID var uuid = UUID(uuidString: yourString) This will return nil if yourString is not a valid UUID Note: this only validates the first case you presented, not the second but adding the dashes yourself is trivial.
I found this question while I was looking for a Python answer. To help people in the same situation, I’ve added the Python solution. You can use the uuid module: #!/usr/bin/env python from uuid import UUID def is_valid_uuid(uuid_to_test, version=4): “”” Check if uuid_to_test is a valid UUID. Parameters ———- uuid_to_test : str version : {1, … Read more
This is one way: df[‘uuid’] = [uuid.uuid4() for _ in range(len(df.index))]
When dealing with UUID numbers store them as data type uuid. Always. There is simply no good reason to even consider text as alternative. Input and output is done via text representation by default anyway. The cast is very cheap. The data type text requires more space in RAM and on disk, is slower to … Read more