Why is the “this” inside of of the Clickers’ click method referring to the dom node rather than … itself? Because the specification for .addEventListener() is to set the this pointer to the DOM element that caught the event. That’s how it is designed to work. When passing a method as a callback where you … Read more
To document instance members, use @name Class#member: /** * Construct a new component * * @class Component * @classdesc A generic component * * @param {Object} options – Options to initialize the component with * @param {String} options.name – This component’s name, sets {@link Component#name} * @param {Boolean} options.visible – Whether this component is visible, … Read more
From MDN documentation Static method calls are made directly on the class and are not callable on instances of the class. Static methods are often used to create utility functions. For more please see=> https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Classes/static You can do something like this => this.constructor.staticMethod()); to call static method. class StaticMethodCall { constructor() { console.log(StaticMethodCall.staticMethod()); // ‘static … Read more
As an alternative to calling an initialization method from all constructors (which prevents you from using readonly fields) or factory methods (which introduce additional complexity when you have derived classes), you can use a parameter object: int a, b, c; public Constructor() : this(new ConstructorParameters()) { } public Constructor(int x, int y) : this(new ConstructorParameters(x, … Read more
This is constructor overloading: public class Diagraph { public Diagraph(int n) { // Constructor code } public Digraph(In in) { this(in.readInt()); // Calls the constructor above. int E = in.readInt(); for (int i = 0; i < E; i++) { int v = in.readInt(); int w = in.readInt(); addEdge(v, w); } } } You can … Read more
Because this refers to the object instance. There is no object instance in a call of a static method. But of course you can access your static field (only the static ones!). Just use class Sub { static int y; public static void foo() { y = 10; } } If you want to make … Read more
So is the this pointer just a compile time thing and not an actual pointer? It very much is a run time thing. It refers to the object on which the member function is invoked, naturally that object can exist at run time. What is a compile time thing is how name lookup works. When … Read more
Leaking the this reference in the constructor (not controller) is dangerous, especially in a multithreaded environment. This is because the object is not fully constructed until the constructor call finishes. Leaking this from the constructor thus means that the external world gets access to an object which is not yet fully constructed. This may not … Read more
this is a pointer, and *this is a dereferenced pointer. If you had a function that returned this, it would be a pointer to the current object, while a function that returned *this would be a “clone” of the current object, allocated on the stack — unless you have specified the return type of the … Read more
Why is JavaScript bind() necessary? The value of this is determined by how a function is called. If it is you who calls the function then there is usually no need to use .bind, since you have control over how to call the function, and therefore its this value. However, often it is not you … Read more