You should use sum: Total = df[‘MyColumn’].sum() print(Total) 319 Then you use loc with Series, in that case the index should be set as the same as the specific column you need to sum: df.loc[‘Total’] = pd.Series(df[‘MyColumn’].sum(), index=[‘MyColumn’]) print(df) X MyColumn Y Z 0 A 84.0 13.0 69.0 1 B 76.0 77.0 127.0 2 C … Read more
using System.Linq; … double total = myList.Sum(item => item.Amount);
You can just sum and set param axis=1 to sum the rows, this will ignore none numeric columns: In [91]: df = pd.DataFrame({‘a’: [1,2,3], ‘b’: [2,3,4], ‘c’:[‘dd’,’ee’,’ff’], ‘d’:[5,9,1]}) df[‘e’] = df.sum(axis=1) df Out[91]: a b c d e 0 1 2 dd 5 8 1 2 3 ee 9 14 2 3 4 ff 1 … Read more
As you’d expect: sum(d.values())
Question 1: To sum a list of numbers, use sum: xs = [1, 2, 3, 4, 5] print(sum(xs)) This outputs: 15 Question 2: So you want (element 0 + element 1) / 2, (element 1 + element 2) / 2, … etc. We make two lists: one of every element except the first, and one … Read more
For ruby >= 2.4 you can use sum: array.sum For ruby < 2.4 you can use inject: array.inject(0, :+) Note: the 0 base case is needed otherwise nil will be returned on empty arrays: > [].inject(:+) nil > [].inject(0, :+) 0