Find only regular files under current directory, and print them without “./” prefix: find -type f -printf ‘%P\n’ From man find, description of -printf format: %P File’s name with the name of the command line argument under which it was found removed.
In short: strip() is “Unicode-aware” evolution of trim(). Meaning trim() removes only characters <= U+0020 (space); strip() removes all Unicode whitespace characters (but not all control characters, such as \0) CSR : JDK-8200378 Problem String::trim has existed from early days of Java when Unicode had not fully evolved to the standard we widely use today. … Read more
Use this: if(typeof(String.prototype.trim) === “undefined”) { String.prototype.trim = function() { return String(this).replace(/^\s+|\s+$/g, ”); }; } The trim function will now be available as a first-class function on your strings. For example: ” dog”.trim() === “dog” //true EDIT: Took J-P’s suggestion to combine the regex patterns into one. Also added the global modifier per Christoph’s suggestion. … Read more
Try os.path.splitext it should do what you want. import os print os.path.splitext(‘/home/user/somefile.txt’)[0]+’.jpg’ # /home/user/somefile.jpg os.path.splitext(‘/home/user/somefile.txt’) # returns (‘/home/user/somefile’, ‘.txt’)
Taking advantage of str.split’s behavior with no sep parameter: >>> s = ” \t foo \n bar ” >>> “”.join(s.split()) ‘foobar’ If you just want to remove spaces instead of all whitespace: >>> s.replace(” “, “”) ‘\tfoo\nbar’ Premature optimization Even though efficiency isn’t the primary goal—writing clear code is—here are some initial timings: $ python … Read more
Use list comprehension — simpler, and just as easy to read as a for loop. my_string = “blah, lots , of , spaces, here ” result = [x.strip() for x in my_string.split(‘,’)] # result is [“blah”, “lots”, “of”, “spaces”, “here”] See: Python docs on List Comprehension A good 2 second explanation of list comprehension.
For whitespace on both sides, use str.strip: s = ” \t a string example\t ” s = s.strip() For whitespace on the right side, use str.rstrip: s = s.rstrip() For whitespace on the left side, use str.lstrip: s = s.lstrip() You can provide an argument to strip arbitrary characters to any of these functions, like … Read more