Order matters If you want to keep your array ordered, you have to shift all of the elements at the right of the deleting index by one to the left. Hopefully, this can be done easily in Golang: func remove(slice []int, s int) []int { return append(slice[:s], slice[s+1:]…) } However, this is inefficient because you … Read more
Possible reason 1: trying to create a jagged array You may be creating an array from a list that isn’t shaped like a multi-dimensional array: numpy.array([[1, 2], [2, 3, 4]]) # wrong! numpy.array([[1, 2], [2, [3, 4]]]) # wrong! In these examples, the argument to numpy.array contains sequences of different lengths. Those will yield this … Read more
2017 Answer – pandas 0.20: .ix is deprecated. Use .loc See the deprecation in the docs .loc uses label based indexing to select both rows and columns. The labels being the values of the index or the columns. Slicing with .loc includes the last element. Let’s assume we have a DataFrame with the following columns: … Read more
The two alternative you gave are semantically identical, but using make([]int, 0) will result in an internal call to runtime.makeslice (Go 1.16). You also have the option to leave it with a nil value: var myslice []int As written in the Golang.org blog: a nil slice is functionally equivalent to a zero-length slice, even though … Read more
it means ‘nothing for the first argument, nothing for the second, and jump by three’. It gets every third item of the sequence sliced. Extended slices is what you want. New in Python 2.3
This is an old question, but here’s my two cents. PeterSO’s answer is slightly more concise, but slightly less efficient. You already know how big it’s going to be so you don’t even need to use append: keys := make([]int, len(mymap)) i := 0 for k := range mymap { keys[i] = k i++ } … Read more
Mostafa has already pointed out that such a method is trivial to write, and mkb gave you a hint to use the binary search from the sort package. But if you are going to do a lot of such contains checks, you might also consider using a map instead. It’s trivial to check if a … Read more
You can use negative integers with the slicing operator for that. Here’s an example using the python CLI interpreter: >>> a = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12] >>> a [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12] >>> a[-9:] [4, 5, 6, 7, 8, … Read more
You should use reflect.DeepEqual() DeepEqual is a recursive relaxation of Go’s == operator. DeepEqual reports whether x and y are “deeply equal,” defined as follows. Two values of identical type are deeply equal if one of the following cases applies. Values of distinct types are never deeply equal. Array values are deeply equal when their … Read more
Array.prototype.pop() by JavaScript convention. let fruit = [‘apple’, ‘orange’, ‘banana’, ‘tomato’]; let popped = fruit.pop(); console.log(popped); // “tomato” console.log(fruit); // [“apple”, “orange”, “banana”]