There isn’t a more concise way, what you did is the “right” way; because slices are always one-dimensional but may be composed to construct higher-dimensional objects. See this question for more details: Go: How is two dimensional array’s memory representation. One thing you can simplify on it is to use the for range construct: a … Read more
The builtin copy(dst, src) copies min(len(dst), len(src)) elements. So if your dst is empty (len(dst) == 0), nothing will be copied. Try tmp := make([]int, len(arr)) (Go Playground): arr := []int{1, 2, 3} tmp := make([]int, len(arr)) copy(tmp, arr) fmt.Println(tmp) fmt.Println(arr) Output (as expected): [1 2 3] [1 2 3] Unfortunately this is not documented … Read more
Disclaimer: This answer does not conform to the constraints of the question: I don’t want to have to create a new byte array in the heap memory just to do that. (Honestly, I feel my answer is worthy of deletion. The answer by @unique72 is correct. Imma let this edit sit for a bit and … Read more
To answer this question, we have to look at how indexing a multidimensional array works in Numpy. Let’s first say you have the array x from your question. The buffer assigned to x will contain 16 ascending integers from 0 to 15. If you access one element, say x[i,j], NumPy has to figure out the … Read more
The ellipsis is used in numpy to slice higher-dimensional data structures. It’s designed to mean at this point, insert as many full slices (:) to extend the multi-dimensional slice to all dimensions. Example: >>> from numpy import arange >>> a = arange(16).reshape(2,2,2,2) Now, you have a 4-dimensional matrix of order 2x2x2x2. To select all first … Read more
The title of your question is: How to join a slice of strings into a single string? but in fact, reg is not a slice, but a length-three array. […]string is just syntactic sugar for (in this case) [3]string. To get an actual slice, you should write: reg := []string {“a”,”b”,”c”} (Try it out: https://play.golang.org/p/vqU5VtDilJ.) … Read more
For just reading the last element of a slice: sl[len(sl)-1] For removing it: sl = sl[:len(sl)-1] See this page about slice tricks
What’s happening here is that you call slice() as if it was a function of NodeList using call(). What slice() does in this case is create an empty array, then iterate through the object it’s running on (originally an array, now a NodeList) and keep appending the elements of that object to the empty array … Read more
See the Parameter Expansion section in the Bash man page. A[@] returns the contents of the array, :1:2 takes a slice of length 2, starting at index 1. A=( foo bar “a b c” 42 ) B=(“${A[@]:1:2}”) C=(“${A[@]:1}”) # slice to the end of the array echo “${B[@]}” # bar a b c echo “${B[1]}” … Read more
MultiIndex / Advanced Indexing Note This post will be structured in the following manner: The questions put forth in the OP will be addressed, one by one For each question, one or more methods applicable to solving this problem and getting the expected result will be demonstrated. Notes (much like this one) will be included … Read more