You can use the substring function: let str = “12345.00”; str = str.substring(0, str.length – 1); console.log(str); This is the accepted answer, but as per the conversations below, the slice syntax is much clearer: let str = “12345.00”; str = str.slice(0, -1); console.log(str);
Your approach would take linear time for each insertion. A better way would be to use a map[int]struct{}. Alternatively, you could also use a map[int]bool or something similar, but the empty struct{} has the advantage that it doesn’t occupy any additional space. Therefore map[int]struct{} is a popular choice for a set of integers. Example: set … Read more
Slice notation in short: [ <first element to include> : <first element to exclude> : <step> ] If you want to include the first element when reversing a list, leave the middle element empty, like this: foo[::-1] You can also find some good information about Python slices in general here: Explain Python’s slice notation
The short answer Slicing lists does not generate copies of the objects in the list; it just copies the references to them. That is the answer to the question as asked. The long answer Testing on mutable and immutable values First, let’s test the basic claim. We can show that even in the case of … Read more
You can use the as_bytes method: fn f(s: &[u8]) {} pub fn main() { let x = “a”; f(x.as_bytes()) } or, in your specific example, you could use a byte literal: let x = b”a”; f(x)
Everything in Go is passed by value, slices too. But a slice value is a header, describing a contiguous section of a backing array, and a slice value only contains a pointer to the array where the elements are actually stored. The slice value does not include its elements (unlike arrays). So when you pass … Read more
len() returns the number of elements in a slice or array. Assuming whatever() is the function you invoke, you can do something like: r := whatever() if len(r) > 0 { // do what you want } or if you don’t need the items if len(whatever()) > 0 { // do what you want }
It is an example of slice notation, and what it does depends on the type of population. If population is a list, this line will create a shallow copy of the list. For an object of type tuple or a str, it will do nothing (the line will do the same without [:]), and for … Read more
My favorite way to do it: def pairwise(t): it = iter(t) return zip(it,it) # for “pairs” of any length def chunkwise(t, size=2): it = iter(t) return zip(*[it]*size) When you want to pair all elements you obviously might need a fillvalue: from itertools import izip_longest def blockwise(t, size=2, fillvalue=None): it = iter(t) return izip_longest(*[it]*size, fillvalue=fillvalue) With … Read more
You are confusing two distinct operation that use very similar syntax: 1) slicing: b = a[0:2] This makes a copy of the slice of a and assigns it to b. 2) slice assignment: a[0:2] = b This replaces the slice of a with the contents of b. Although the syntax is similar (I imagine by … Read more