How to choose a weighted random array element in Javascript?

Both answers above rely on methods that will get slow quickly, especially the accepted one. This is a function which just takes two same-length lists, items and weights, and returns a random item from items according to their corresponding likelihoods of being chosen in weights. The weights array should be of nonnegative numbers, but it … Read more

select from one table, insert into another table oracle sql query

From the oracle documentation, the below query explains it better INSERT INTO tbl_temp2 (fld_id) SELECT tbl_temp1.fld_order_id FROM tbl_temp1 WHERE tbl_temp1.fld_order_id > 100; You can read this link Your query would be as follows //just the concept INSERT INTO quotedb (COLUMN_NAMES) //seperated by comma SELECT COLUMN_NAMES FROM tickerdb,quotedb WHERE quotedb.ticker = tickerdb.ticker Note: Make sure the … Read more

MySQL INNER JOIN Alias

You’ll need to join twice: SELECT home.*, away.*, g.network, g.date_start FROM game AS g INNER JOIN team AS home ON home.importid = g.home INNER JOIN team AS away ON away.importid = g.away ORDER BY g.date_start DESC LIMIT 7

select from values in mysql

From the link you provided : VALUES (1, ‘one’), (2, ‘two’), (3, ‘three’); This will return a table of two columns and three rows. It’s effectively equivalent to: SELECT 1 AS column1, ‘one’ AS column2 UNION ALL SELECT 2, ‘two’ UNION ALL SELECT 3, ‘three’; So you need select * from table1, ( SELECT 1 … Read more

Break out of select loop?

The Go spec says: A “break” statement terminates execution of the innermost “for”, “switch”, or “select” statement within the same function. In your example you’re just breaking out of the select statement. If you replace break with a return statement you will see that it’s working.

SQL to select all rows with duplicate values in one column

You could use windowed COUNT: SELECT sub.name, sub.employee_id FROM (SELECT *, COUNT(*) OVER(PARTITION BY employee_id) AS c FROM users) AS sub WHERE c > 1; LiveDemo or simple IN: SELECT * FROM users WHERE employee_id IN (SELECT employee_id FROM users GROUP BY employee_id HAVING COUNT(employee_id) > 1); LiveDemo2 or correlated subquery: SELECT name, employee_id FROM … Read more

Hata!: SQLSTATE[HY000] [1045] Access denied for user 'divattrend_liink'@'localhost' (using password: YES)